我有一块JSON,看起来像这样:
{
"authors": {
"author": [
{
"given-name": "Adrienne H.",
"surname": "Kovacs"
},
{
"given-name": "Philip",
"surname": "Moons"
}
]
}
}
我创建了一个存储作者信息的类:
public class Author {
@JsonProperty("given-name")
public String givenName;
public String surname;
}
两个包装类:
public class Authors {
public List<Author> author;
}
public class Response {
public Authors authors;
}
这是有效的,但似乎没有必要使用两个包装类。我想找到一种方法来删除Authors
类并将列表作为Entry类的属性。杰克逊有可能做到这样吗?
使用自定义反序列化器解决了这个问题:
public class AuthorArrayDeserializer extends JsonDeserializer<List<Author>> {
private static final String AUTHOR = "author";
private static final ObjectMapper mapper = new ObjectMapper();
private static final CollectionType collectionType =
TypeFactory
.defaultInstance()
.constructCollectionType(List.class, Author.class);
@Override
public List<Author> deserialize(JsonParser jsonParser, DeserializationContext deserializationContext)
throws IOException, JsonProcessingException {
ObjectNode objectNode = mapper.readTree(jsonParser);
JsonNode nodeAuthors = objectNode.get(AUTHOR);
if (null == nodeAuthors // if no author node could be found
|| !nodeAuthors.isArray() // or author node is not an array
|| !nodeAuthors.elements().hasNext()) // or author node doesn't contain any authors
return null;
return mapper.reader(collectionType).readValue(nodeAuthors);
}
}
并像这样使用它:
@JsonDeserialize(using = AuthorArrayDeserializer.class)
public void setAuthors(List<Author> authors) {
this.authors = authors;
}
感谢@wassgren的想法。
答案 0 :(得分:10)
如果你想摆脱包装类,我至少看到两种方法。第一种是使用Jackson树模型(JsonNode
),第二种是使用名为UNWRAP_ROOT_VALUE
的反序列化功能。
备选方案1:使用JsonNode
使用Jackson反序列化JSON时,有多种方法可以控制要创建的对象类型。 ObjectMapper
可以将JSON反序列化为例如Map
,JsonNode
(通过readTree
- 方法)或POJO。
如果将readTree
- 方法与POJO
转换结合使用,则可以完全删除包装器。例如:
// The author class (a bit cleaned up)
public class Author {
private final String givenName;
private final String surname;
@JsonCreator
public Author(
@JsonProperty("given-name") final String givenName,
@JsonProperty("surname") final String surname) {
this.givenName = givenName;
this.surname = surname;
}
public String getGivenName() {
return givenName;
}
public String getSurname() {
return surname;
}
}
反序列化可以看起来像这样:
// The JSON
final String json = "{\"authors\":{\"author\":[{\"given-name\":\"AdrienneH.\",\"surname\":\"Kovacs\"},{\"given-name\":\"Philip\",\"surname\":\"Moons\"}]}}";
ObjectMapper mapper = new ObjectMapper();
// Read the response as a tree model
final JsonNode response = mapper.readTree(json).path("authors").path("author");
// Create the collection type (since it is a collection of Authors)
final CollectionType collectionType =
TypeFactory
.defaultInstance()
.constructCollectionType(List.class, Author.class);
// Convert the tree model to the collection (of Author-objects)
List<Author> authors = mapper.reader(collectionType).readValue(response);
// Now the authors-list is ready to use...
如果使用此树模型方法,则可以完全删除包装类。
备选方案2:删除其中一个包装并解开根值
第二种方法是只删除一个包装器。假设您删除Authors
类,但保留Response
- 包装器。如果添加a @JsonRootName
- 注释,稍后可以打开顶级名称。
@JsonRootName("authors") // This is new compared to your example
public class Response {
private final List<Author> authors;
@JsonCreator
public Response(@JsonProperty("author") final List<Author> authors) {
this.authors = authors;
}
@JsonProperty("author")
public List<Author> getAuthors() {
return authors;
}
}
然后,对于您的映射器,只需使用:
ObjectMapper mapper = new ObjectMapper();
// Unwrap the root value i.e. the "authors"
mapper.configure(DeserializationFeature.UNWRAP_ROOT_VALUE, true);
final Response responsePojo = mapper.readValue(json, Response.class);
第二种方法只删除了一个包装类,而是解析函数非常漂亮。