我是javasript的新手 我有简单的代码,在谷歌chroome工作正常,但剧本din't firefox 它只是关于onmouseover和onmouseout的两个事件并且更改图像
<!DOCTYPE html>
<html>
<head>
<title> </title>
<script>
function over() {
image1.src = "13.JPG"
}
function out() {
image1.src = "19.JPG"
}
</script>
<style>
img {
height:200px; width:200px;
}
</style>
</head>
<body>
<img id="image1" onmouseover="over()" onmouseout="out()" />
</body>
</html>
它在谷歌chroome中运行良好,但在firefox中没有,我想知道原因,谢谢。
答案 0 :(得分:0)
以下是如何使用javascript:
执行此操作
function over() {
document.getElementById('image1').src = "http://animalrescuetracy.org/wp-content/uploads/2014/07/playful-kitten-6683.jpg";
}
function out() {
document.getElementById('image1').src = "http://www.valleyvet.com/images/worming-your-kitten.png";
}
&#13;
img {
height:200px; width:200px;
}
&#13;
<img id="image1" src="" onmouseover="over()" onmouseout="out()"/>
&#13;
以下是如何使用css:
#image1{
content:url("http://www.valleyvet.com/images/worming-your-kitten.png");
height:200px; width:200px;
}
#image1:hover{
content:url("http://animalrescuetracy.org/wp-content/uploads/2014/07/playful-kitten-6683.jpg");
}
&#13;
<img id="image1" src=""/>
&#13;