mySQL报告只显示负面结果

时间:2015-01-09 14:09:20

标签: mysql sql

我正在运行下面的mySQL报告,但只想显示方差的负值。我试过检查"其中"条款,但由于方差是在飞行中创建的,因此似乎不太可能。我也尝试使用"有",但它出错了。我假设它很简单,我只是缺少。请帮忙。

SELECT GROUP_CONCAT(DISTINCT SAM_VIEW_DISCOVERED_SOFTWARE.PUBLISHER SEPARATOR '\n') 
             AS Publisher, 
       GROUP_CONCAT(DISTINCT SAM_VIEW_DISCOVERED_SOFTWARE.NAME SEPARATOR '\n') 
             AS 'Product',
       GROUP_CONCAT(DISTINCT SAM_VIEW_DISCOVERED_SOFTWARE.MAJOR_VERSION SEPARATOR '\n') 
             AS 'Version',
       GROUP_CONCAT(DISTINCT SAM_VIEW_DISCOVERED_SOFTWARE.CATEGORY SEPARATOR '\n') 
             AS 'Category',
       SUM(DISTINCT FIELD_1) AS 'Licenses',
       GROUP_CONCAT(DISTINCT SAM_VIEW_DISCOVERED_SOFTWARE.INSTALLED_ON SEPARATOR '\n') 
             AS 'Installed',
       SUM(DISTINCT FIELD_1) - GROUP_CONCAT(DISTINCT SAM_VIEW_DISCOVERED_SOFTWARE.INSTALLED_ON     SEPARATOR '\n') 
             AS 'Variance'
FROM SAM_VIEW_DISCOVERED_SOFTWARE 
  LEFT JOIN SAM_VIEW_MACHINE_DISCOVERED_SOFTWARE 
            ON SAM_VIEW_DISCOVERED_SOFTWARE.ID = SAM_VIEW_MACHINE_DISCOVERED_SOFTWARE.ID
  LEFT JOIN MACHINE 
            ON MACHINE.ID = SAM_VIEW_MACHINE_DISCOVERED_SOFTWARE.MACHINE_ID 
  LEFT JOIN ASSET_CATALOG_ASSOCIATION 
            ON ASSET_CATALOG_ASSOCIATION.ASSOCIATED_CATALOG_ID = SAM_VIEW_DISCOVERED_SOFTWARE.ID 
  LEFT JOIN ASSET 
            ON ASSET.ID = ASSET_CATALOG_ASSOCIATION.ASSET_ID 
  LEFT JOIN ASSET_DATA_7 
            ON ASSET_DATA_7.ID = ASSET.ASSET_DATA_ID 
  LEFT JOIN ASSET_FIELD_DEFINITION 
            ON ASSET_FIELD_DEFINITION.ID = ASSET_CATALOG_ASSOCIATION.ASSET_FIELD_ID
WHERE FIELD_1 > 0 
GROUP BY SAM_VIEW_DISCOVERED_SOFTWARE.ID 
ORDER BY PUBLISHER, CATEGORY

0 个答案:

没有答案