Question

我想从mySql查询中排除否定结果。这是我的查询：

SELECT
MAX(datediff(now(), date_ship)) AS days,
date_ship
FROM table

+------------+------+
| date_ship  | days |
+------------+------+
| 2019-07-15 |   -6 |
| 2019-07-12 |   -3 |
| 2019-07-01 |    9 |
| 2019-06-25 |   14 |
+------------+------+

我只想得到负面结果：

+------------+------+
| date_ship  | days |
+------------+------+
| 2019-07-15 |   -6 |
| 2019-07-12 |   -3 |
+------------+------+

Answer 1

正如this comment中指出的那样，您的查询本质上应该是：

SELECT
  MAX(datediff(now(), date_ship)) AS days,
  date_ship
FROM table
GROUP BY date_ship
HAVING MAX(datediff(now(), date_ship)) < 0
;

Answer 2

检查以下查询并尝试。

SELECT MAX(datediff(now(), date_ship)) AS days,
date_ship
FROM table WHERE MAX(datediff(now(), date_ship)) < 0;

从MySQL查询中排除否定结果

2 个答案: