我有一个python脚本,它调用系统程序并从文件out.txt
读取输出,作用于该输出,并循环。但是,它不起作用,并且仔细调查显示python脚本只打开out.txt
一次,然后继续从该旧副本读取。如何让python脚本在每次迭代时重新读取文件?我在这里看到了一个类似的问题,但它是关于一个与程序一起运行的python脚本,而不是调用它,并且该解决方案不起作用。我试图在循环回来之前关闭文件,但它没有做任何事情。
编辑: 我已经尝试过关闭和打开,它没有工作。这是代码:
import subprocess, os, sys
filename = sys.argv[1]
file = open(filename,'r')
foo = open('foo','w')
foo.write(file.read().rstrip())
foo = open('foo','a')
crap = open(os.devnull,'wb')
numSolutions = 0
while True:
subprocess.call(["minisat", "foo", "out"], stdout=crap,stderr=crap)
out = open('out','r')
if out.readline().rstrip() == "SAT":
numSolutions += 1
clause = out.readline().rstrip()
clause = clause.split(" ")
print clause
clause = map(int,clause)
clause = map(lambda x: -x,clause)
output = ' '.join(map(lambda x: str(x),clause))
print output
foo.write('\n'+output)
out.close()
else:
break
print "There are ", numSolutions, " solutions."
答案 0 :(得分:3)
您需要刷新foo
,以便外部程序可以查看其最新更改。写入文件时,数据将在本地进程中缓冲,并以较大的块发送到系统。这样做是因为更新系统文件相对昂贵。在您的情况下,您需要强制刷新数据,以便minisat可以看到它。
foo.write('\n'+output)
foo.flush()
答案 1 :(得分:1)
我重写了它,希望有点容易理解:
import os
from shutil import copyfile
import subprocess
import sys
TEMP_CNF = "tmp.in"
TEMP_SOL = "tmp.out"
NULL = open(os.devnull, "wb")
def all_solutions(cnf_fname):
"""
Given a file containing a set of constraints,
generate all possible solutions.
"""
# make a copy of original input file
copyfile(cnf_fname, TEMP_CNF)
while True:
# run minisat to solve the constraint problem
subprocess.call(["minisat", TEMP_CNF, TEMP_SOL], stdout=NULL,stderr=NULL)
# look at the result
with open(TEMP_SOL) as result:
line = next(result)
if line.startswith("SAT"):
# Success - return solution
line = next(result)
solution = [int(i) for i in line.split()]
yield solution
else:
# Failure - no more solutions possible
break
# disqualify found solution
with open(TEMP_CNF, "a") as constraints:
new_constraint = " ".join(str(-i) for i in sol)
constraints.write("\n")
constraints.write(new_constraint)
def main(cnf_fname):
"""
Given a file containing a set of constraints,
count the possible solutions.
"""
count = sum(1 for i in all_solutions(cnf_fname))
print("There are {} solutions.".format(count))
if __name__=="__main__":
if len(sys.argv) == 2:
main(sys.argv[1])
else:
print("Usage: {} cnf.in".format(sys.argv[0]))
答案 2 :(得分:0)
你接受file_var并用file_var.close()结束循环。
for ... :
ga_file = open(out.txt, 'r')
... do stuff
ga_file.close()
下面的一个实现的演示(尽可能简单,这是所有需要的Jython代码)......
__author__ = ''
import time
var = 'false'
while var == 'false':
out = open('out.txt', 'r')
content = out.read()
time.sleep(3)
print content
out.close()
生成此输出:
2015-01-09, 'stuff added'
2015-01-09, 'stuff added' # <-- this is when i just saved my update
2015-01-10, 'stuff added again :)' # <-- my new output from file reads
我强烈建议您阅读错误消息。他们掌握了很多信息。
我认为应该编写完整的文件名以用于调试目的。