Question

我学习Python（Windows 7上的Python 3.4）。当我在pycharm IDE中运行以下代码时，它运行正常，但是当它在codeeval.com challenge中作为解决方案提交时，它会给出错误IOError：[Errno 2]没有这样的文件或目录：＆＃39; D： /Trial/simple.txt' ;.为什么这样？。通过在线解释器（Codeeval提交窗口）读取位于本地磁盘上的文件的正确方法是什么。

path = "D:/Trial/simple.txt"
file = open(path,"r+")
age = file.read().split()
for i in range(0,len(age)):
    if int(age[i]) <= 2:
        print("Still in Mama's arms")
    if 4 == int(age[i]) == 3:
        print("Preschool Maniac")
    if 5 <= int(age[i]) >= 11:
        print("Elementary school")
    if  12 <= int(age[i]) >= 14:
        print("Middle school")
    if  15 <= int(age[i]) >= 18:
        print("High school")
    if  19 <= int(age[i]) >= 22:
        print("College")
    if 23 <= int(age[i]) >= 65:
        print("Working for the man")
    if 66 <= int(age[i]) >= 100:
       print("The Golder years")
file.close()

Answer 1

你的链式条件不符合你的期望。 a compare b compare c == a compare b and b compare c。因此，4 == int(age[i]) == 3永远不会成立，5 <= int(age[i]) >= 11 == int(age[i]) >= 11。

您没有指定年龄是在一行上还是在单独一行上。无论哪种方式，以下都应该有效。请注意，可以直接遍历列表而不使用range。

import sys
ages = sys.stdin.read().split()
for age in sys.stdin.read().split():
    age = int(age)
    if age <= 2:
        print("Still in Mama's arms")
    if 3 <= age <= 4:
        print("Preschool Maniac")
    if 5 <= age <= 11:
        print("Elementary school")
    ...

从本地磁盘读取文件

1 个答案: