Question

如果值位于模式中没有的有效负载中，是否可以使用漏勺引发错误？因此，只允许列入白名单的字段？

这是一个示例：

# coding=utf-8
from colander import MappingSchema, String, Length
from colander import SchemaNode


class SamplePayload(MappingSchema):
    name = SchemaNode(String())
    foo  = SchemaNode(Int())


class Sample(MappingSchema):
    type = SchemaNode(String(), validator=Length(max=32))
    payload = SamplePayload()

# This json should not be accepted (and should yield something like: Unknown field in payload: bar

{  
   "type":"foo",
   "payload":{  
      "name":"a name",
      "foo":123,
      "bar":false
   }
}

Answer 1

是的，请参阅the docs of colander.Mapping

使用colander.Mapping(unknown='raise')创建映射将导致在反序列化期间cstruct中存在未知密钥时引发colander.Invalid异常。

根据issue 116 in the tracker，将其应用于Schema对象的方法是覆盖schema_type方法：

class StrictMappingSchema(MappingSchema):
    def schema_type(self, **kw):
        return colander.Mapping(unknown='raise')

class SamplePayload(StrictMappingSchema):
    name = SchemaNode(String())
    foo  = SchemaNode(Int())

禁止未知的价值观？

1 个答案: