Question

我正在用Java开发一个简单的AI游戏：Dots and Boxes。现在，它将是2 * 2。状态由两个矩阵表示：水平矩阵和垂直矩阵。例如：州

  --   --
|    |    |
  --  
|    |    |
  --   --

由水平矩阵表示：

int[][] horz = new int[][] {{1,1}, {1,0}, {1,1} };

和垂直矩阵：

int[][] ver = new int[][] { {1,1,1}, {1,1,1} };

目前，我不打算使用GUI。我有这两个矩阵。所以，给它们作为输入，我想要做的只是使用下面的代码在终端中显示状态图（如上所示），但我没有得到正确的结果。

for(int horz_row=0; horz_row<horz.length; horz_row++) //print horz matrix row 
{ 
    //after one row break, print the first row of vertical column 
    System.out.print(horz[horz_row][horz_col]); 
    for(int ver_row=0;ver_row<ver.length; ver_row++) //print vertical matrix, row 
    {
        System.out.print(ver[horz_row][horz_col]); 
    } 
    System.out.print("  "); 
}

Answer 1

int[][] hor = new int[][] {{1,1}, {1,0}, {1,1} };
int[][] ver = new int[][] { {1,1,1}, {1,1,1} };

String[] vstr = { " ", "|" };
String[] hstr = { "  ", "--" };
for( int iRow = 0; iRow < ver.length + 1; ++iRow ){
    StringBuilder sbh = new StringBuilder( " " );
    String delh = "";
    for( int iCol = 0; iCol < hor[iRow].length; ++iCol ){
        sbh.append(delh).append( hstr[hor[iRow][iCol]] );
        delh = " ";
    }
    System.out.println(sbh.toString());
    if( iRow < ver.length ){
        StringBuilder sbv = new StringBuilder();
        String delv = "";
        for( int iCol = 0; iCol < ver[iRow].length; ++iCol ){
            sbv.append(delv).append( vstr[ver[iRow][iCol]] );
            delv = "  ";
        }
        System.out.println(sbv.toString());
    }
}

Answer 2

这应该有效：

在此处试试：http://ideone.com/iv082V

public static void main (String[] args) throws java.lang.Exception
{
    int[][] horz = new int[][] {{1,1}, {1,0}, {1,1} };
    int[][] ver  = new int[][] { {1,1,1}, {1,1,1} };

    createMatrices(horz, ver);
}

public static void createMatrices(int[][] horz, int[][] ver) 
{
    for (int i = 0; i < horz.length-1; i++) {
        for (int j = 0; j < horz[i].length; j++) {
            System.out.print(horz[i][j]==1?"  -- ":"     ");
        }
        System.out.println();
        for (int k = 0; k < ver[i].length; k++) {
            System.out.print(ver[i][k]==1?"|    ":"     ");
        }
        System.out.println();
    }
    // print last row of hyphens
    int i = horz.length - 1;
    for (int j = 0; j < horz[i].length; j++) {
        System.out.print(horz[i][j]==1?"  -- ":"     ");
    }
    System.out.println();
}

使用for循环和矩阵绘制点和框

2 个答案: