在c#中返回给定接口的泛型类型

时间:2015-01-06 14:22:37

标签: c# generics interface

假设我有以下设置。

Interface IDALModel {}

各种类实现此接口......

class AddressModel : IDALModel 
{
    public int AddressId {get;set;}
    public string Address {get;set;}
}

class AccountModel : IDALModel
{
    public int AccountId {get;set;}
    public string Name {get;set;}
}

class TenantModel : IDALModel
{
    public int TenantId {get;set;}
    public KeyedCollection<int, AddressModel> Addresses {get;set;}
}

在另一个类中,我有一个方法应该以通用的方式返回一个类的实例。

class SomeClass
{
    internal DataFieldBuilder<IDALModel> Embed<T>(Expression<Func<T, object>> embed, string alias = "")
    {
        PropertyInfo propertyInfo = GetPropertyInfo(embed);
        Type type = propertyInfo.PropertyType.GenericTypeArguments[1];
        DataFieldBuilder<IDALModel> returnObject = new DataFieldBuilder<type>();
    }

    private PropertyInfo GetPropertyInfo<T>(Expression<Func<T, object>> field)
    {
        PropertyInfo propertyInfo;
        if (field.Body is UnaryExpression)
        {
            propertyInfo = ((MemberExpression)((UnaryExpression)field.Body).Operand).Member as PropertyInfo;
        }
        else
        {
            propertyInfo = ((MemberExpression)field.Body).Member as PropertyInfo;
        }

        return propertyInfo;
    }
}

从其他地方调用Embed方法

DataFieldBuilder<IDALModel> Addresses = test.Embed<TenantModel>(t => t.Addresses);

我在embed方法中尝试做的是从属性AddressModel中提取基础类型TenantModel.Addresses并创建DataFieldBuilder<AddressModel>的实例

这行失败

DataFieldBuilder<IDALModel> returnObject = new DataFieldBuilder<type>();

带有消息&#34;无法将DataFieldBuilder<AddressModel>隐式转换为DataFieldBuilder<IDALModel>

我希望,因为接口IDALModel是由AddressModel实现的,所以它可以工作。不知道我在这里缺少什么。

为了进行测试,我甚至尝试对一些例子进行硬编码,例如

DataFieldBuilder<IDALModel> returnObject = new DataFieldBuilder<AddressModel>();

这也会产生同样的错误。

2 个答案:

答案 0 :(得分:5)

您可以使用通用方法定义并对其强制实施接口约束:

class SomeClass
{
    public DataFieldBuilder<T> Embed<T>() where T: IDALModel
    {
        var returnObject = new DataFieldBuilder<T>();
        return returnObject;
    }
}

答案 1 :(得分:0)

你想要协方差:

public IDataFieldBuilder<IDALModel> Embed<T>() where T : IDALModel
{
    IDataFieldBuilder<IDALModel> returnObject = (IDataFieldBuilder<IDALModel>)new DataFieldBuilder<T>();
    return returnObject;
}

interface IDALModel {}

class AddressModel : IDALModel 
{
    public int AddressId {get;set;}
    public string Address {get;set;}
}

class AccountModel : IDALModel
{
    public int AccountId {get;set;}
    public string Name {get;set;}
}

class DataFieldBuilder<T> : IDataFieldBuilder<T>
{

}

interface IDataFieldBuilder<out T>
{

}