在T-SQL中,是否可以为我提供包含指定列值的表和列的列表?
例如,我从SQL Server数据库生成一个员工报告,该报告在其中一列中显示“John”作为名称。现在我想找出“John”在数据库的任何表/列中作为字段值出现的位置。
所以在英语中我的查询应该听起来像;
Select table, column
from database A
where field = 'John'
由于
答案 0 :(得分:2)
尝试使用此程序
CREATE PROCEDURE FindMyData_String @DataToFind NVARCHAR(4000),
@ExactMatch BIT = 0
AS
SET NOCOUNT ON
DECLARE @Temp TABLE
(
RowId INT IDENTITY(1, 1),
SchemaName SYSNAME,
TableName SYSNAME,
ColumnName SYSNAME,
DataType VARCHAR(100),
DataFound BIT
)
INSERT INTO @Temp
(TableName,
SchemaName,
ColumnName,
DataType)
SELECT C.Table_Name,
C.TABLE_SCHEMA,
C.Column_Name,
C.Data_Type
FROM Information_Schema.Columns AS C
INNER JOIN Information_Schema.Tables AS T
ON C.Table_Name = T.Table_Name
AND C.TABLE_SCHEMA = T.TABLE_SCHEMA
WHERE Table_Type = 'Base Table'
AND Data_Type IN ( 'ntext', 'text', 'nvarchar', 'nchar',
'varchar', 'char' )
DECLARE @i INT
DECLARE @MAX INT
DECLARE @TableName SYSNAME
DECLARE @ColumnName SYSNAME
DECLARE @SchemaName SYSNAME
DECLARE @SQL NVARCHAR(4000)
DECLARE @PARAMETERS NVARCHAR(4000)
DECLARE @DataExists BIT
DECLARE @SQLTemplate NVARCHAR(4000)
SELECT @SQLTemplate = CASE
WHEN @ExactMatch = 1 THEN 'If Exists(Select *
From ReplaceTableName
Where Convert(nVarChar(4000), [ReplaceColumnName])
= '''
+ @DataToFind
+ '''
)
Set @DataExists = 1
Else
Set @DataExists = 0'
ELSE 'If Exists(Select *
From ReplaceTableName
Where Convert(nVarChar(4000), [ReplaceColumnName])
Like ''%'
+ @DataToFind
+ '%''
)
Set @DataExists = 1
Else
Set @DataExists = 0'
END,
@PARAMETERS = '@DataExists Bit OUTPUT',
@i = 1
SELECT @i = 1,
@MAX = MAX(RowId)
FROM @Temp
WHILE @i <= @MAX
BEGIN
SELECT @SQL = REPLACE(REPLACE(@SQLTemplate, 'ReplaceTableName', QUOTENAME(SchemaName) + '.'
+ QUOTENAME(TableName)), 'ReplaceColumnName', ColumnName)
FROM @Temp
WHERE RowId = @i
PRINT @SQL
EXEC SP_EXECUTESQL
@SQL,
@PARAMETERS,
@DataExists = @DataExists OUTPUT
IF @DataExists = 1
UPDATE @Temp
SET DataFound = 1
WHERE RowId = @i
SET @i = @i + 1
END
SELECT SchemaName,
TableName,
ColumnName
FROM @Temp
WHERE DataFound = 1
EXEC FindMyData_String
@DataToFind='Enter Your String'