我一直在尝试从JSON文档中获取数据,以按字母顺序输入/输入HTML文档。我在堆栈溢出时发现了类似的请求;但是,在实现当前代码的解决方案时,JSON数据不会根据需要进行重组。
当前代码:
$(document).ready(function() {
//Content Viewer Information
function checkViewers() {
//Base Variables
var viewer = $('#viewed span.user');
var totalViews = $('#viewed span.user').length;
var shortenViews = $('#viewed span.user').length -1;
if (totalViews === 0) {
$('<span> 0 people have </span>').insertBefore($('#viewed span:last-child'));
}
if (totalViews === 2) {
$('<span> and </span>').insertAfter(viewer.first());
}
if (totalViews >= 3) {
viewer.slice(1).hide();
$('<span> and </span>').insertAfter(viewer.first());
$('<span class="user count"></span>').insertAfter(viewer.eq(2));
$('.count').html(shortenViews + ' more people');
}
}
//JSON Data
var xhr = new XMLHttpRequest();
//Sort Alphabetically
function SortAlphabetically(a, b) {
a = a.toLowerCase();
b = b.toLowerCase();
return (a < b) ? -1 : (a > b) ? 1 : 0;
}
xhr.onload = function() {
if (xhr.status === 200) {
responseObject = JSON.parse(xhr.responseText);
var newViewers = '';
for (var i = 0; i < responseObject.profiles.length; i++) {
newViewers += '<span class="user">' + responseObject.profiles[i].firstName + ' ';
newViewers += responseObject.profiles[i].lastName + '</span>';
newViewers += ' ';
}
responseObject.profiles.sort(function(a, b) {
return SortAlphabetically(a.firstName, b.firstName);
});
console.log('JSON Sorted');
//Update Page With New Content
var viewerSection = $('#viewed');
viewerSection.html(newViewers);
}
};
xhr.open('GET', 'data.json', true);
xhr.send(null);
checkViewers();
});
我不确定这个问题的解决方案是什么,或者是否可能有更好的方向来按字母顺序排序JSON数据。任何建议或帮助表示赞赏。
查看当前代码和示例Plunker。
答案 0 :(得分:1)
您在构建HTML之后对数据进行排序。将呼叫转移到responseObject.profiles.sort
循环上方的for
:
//excerpt from the code you provided
//See the plunk for full code
xhr.onload = function() {
if (xhr.status === 200) {
responseObject = JSON.parse(xhr.responseText);
//SORT BEFORE GENERATING HTML
responseObject.profiles.sort(function(a, b) {
return SortAlphabetically(a.firstName, b.firstName);
});
console.log('JSON Sorted');
var newViewers = '';
for (var i = 0; i < responseObject.profiles.length; i++) {
newViewers += '<span class="user">' + responseObject.profiles[i].firstName + ' ';
newViewers += responseObject.profiles[i].lastName + '</span>';
newViewers += ' ';
}
//End of excerpt
答案 1 :(得分:0)
var objectArrayList = [{x:1,y:"Gazi"},{x:1,y:"Ahmet"},{x:1,y:"Fatih"},{x:1,y:"Ertuğrul"}];
objectArrayList .sort(function(x1,x2){return x1.y>x2.y;});
$(objectArrayList).each(function(x){
$("body").append(this.y+"<br>");
});
$("body").append("<b>REVERSE</b><br>");
var objectArrayList = [{x:1,y:"Gazi"},{x:1,y:"Ahmet"},{x:1,y:"Fatih"},{x:1,y:"Ertuğrul"}];
objectArrayList .sort(function(x1,x2){return x1.y<x2.y;});
$(objectArrayList).each(function(x){
$("body").append(this.y+"<br>");
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body></body>
&#13;