Question

我需要能够按类别名称组织我的JSON。我按类别ID（项目）和密钥（类别）将两个表链接在一起。我希望能够组织标记有类别ID的所有项目，以便在类别表中的类别名称下进行组织。到目前为止，这是我的代码：

$query = "SELECT * FROM items,category WHERE items.category_id = category.key";
$result = mysql_query($query,$link) or die('Errant query:  '.$query);
 while($row = mysql_fetch_array($result))

extract($row);
    $channel['items'][] = array(
          'title' => $title,
    'category_id' => $category_id,
    'category_name' => $category_name,
    'category_key' => $key,
    );
}   
    $channels = array($channel);
    $json = json_encode($channel);
    header('Content-type: application/json');
    echo $json;
}

哪个输出JSON如下：

{
"items": [
    {
        "title": "putting in title",
        "category_id": "7",
        "category_name": "Stuff 1",
        "category_key": "7"
    },
    {
        "title": "another title",
        "category_id": "7",
        "category_name": "Stuff 1",
        "category_key": "7"
    },

但我需要按类别名称组织JSON，如下所示：

{
"Stuff 1": [
    {
        "title": "putting in title",
        "category_id": "7",
        "category_name": "Stuff 1",
        "category_key": "7"
    },
    {
        "title": "another title",
        "category_id": "7",
        "category_name": "Stuff 1",
        "category_key": "7"
    },
"Stuff 2": [
    {
        "title": "putting in title",
        "category_id": "7",
        "category_name": "Stuff 2",
        "category_key": "7"
    },
    {
        "title": "another title",
        "category_id": "7",
        "category_name": "Stuff 2",
        "category_key": "7"
    },

非常感谢任何有助于实现这一目标的帮助！

Answer 1

试试这个：

$channel[$category_name][] = array(
      'title' => $title,
'category_id' => $category_id,
'category_name' => $category_name,
'category_key' => $key,
);

PHP MySQL JSON按数据组织

1 个答案: