我正试图达到类似this site的效果。我基本上试图实现一种“比较”两个相似图像(具有不同颜色等)的方法。我设法以一种不太好的方式执行此操作,使用两个PictureBox控件(Winforms),并在MouseMove事件上更改其大小和位置属性。
结果有效,但它会闪烁很多,并不是最好的方法。 有没有更好的方法来做到这一点,可能是使用WPF或以任何方式更改代码?这是:
private void pbImg1_MouseMove(object sender, MouseEventArgs e)
{
pbImg2.Image = CropImage(array[1], new Rectangle(pbImg1.Size.Width, 0, totalSize.Width - pbImg1.Size.Width, 240));
pbImg1.Size = new Size(e.X, pbImg1.Height);
pbImg2.Location = new Point(pbImg1.Size.Width + pbImg1.Location.X, pbImg2.Location.Y);
pbImg2.Size = new Size(totalSize.Width - pbImg1.Size.Width, 240);
lpbImg1Size.Text = pbImg1.Size.ToString();
lpbImg2Size.Text = pbImg2.Size.ToString();
lpbImg1Location.Text = pbImg1.Location.ToString();
lpbImg2Location.Text = pbImg2.Location.ToString();
}
private void pbImg2_MouseMove(object sender, MouseEventArgs e)
{
pbImg1.Image = CropImage(array[0], new Rectangle(0, 0, totalSize.Width - pbImg2.Size.Width, 240));
pbImg1.Size = new Size(pbImg1.Width + e.X, 240);
lpbImg1Size.Text = pbImg1.Size.ToString();
lpbImg2Size.Text = pbImg2.Size.ToString();
lpbImg1Location.Text = pbImg1.Location.ToString();
lpbImg2Location.Text = pbImg2.Location.ToString();
}
public Bitmap CropImage(Bitmap source, Rectangle section)
{
// An empty bitmap which will hold the cropped image
//TRY CATCH
Bitmap bmp = new Bitmap(section.Width, section.Height);
Graphics g = Graphics.FromImage(bmp);
// Draw the given area (section) of the source image
// at location 0,0 on the empty bitmap (bmp)
g.DrawImage(source, 0, 0, section, GraphicsUnit.Pixel);
return bmp;
}
在这里你可以看到程序的行为: https://gfycat.com/VillainousReadyAmazonparrot
答案 0 :(得分:0)
您需要两张与图片框大小相同的 imageLeft,imageRight 图片:
private int pos = 0; //x coordinate of mouse in picturebox
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
if(pos == 0)
{
e.Graphics.DrawImage(Properties.Resources.imageRight, new Rectangle(0, 0, pictureBox1.Width, pictureBox1.Height));
}
else
{
e.Graphics.DrawImage(Properties.Resources.imageLeft, new Rectangle(0, 0, pos, pictureBox1.Height),
new Rectangle(0, 0, pos, pictureBox1.Height), GraphicsUnit.Pixel);
e.Graphics.DrawImage(Properties.Resources.imageRight, new Rectangle(pos, 0, pictureBox1.Width - pos, pictureBox1.Height),
new Rectangle(pos, 0, pictureBox1.Width - pos, pictureBox1.Height), GraphicsUnit.Pixel);
}
}
private void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
pos = e.X;
pictureBox1.Invalidate();
}