这是我的json数据
{"CategoryID":1,"CategoryName":"Clothing","Status":true,"SubCategoryList": [{"Status":true,"SubCategoryID":1,"SubCategoryName":"Male"}, {"Status":true,"SubCategoryID":2,"SubCategoryName":"Female"}, {"Status":true,"SubCategoryID":3,"SubCategoryName":"Kids"}, {"Status":true,"SubCategoryID":4,"SubCategoryName":"New Born Baby"}, {"Status":true,"SubCategoryID":11,"SubCategoryName":"Sun Glasses"}]}, {"CategoryID":2,"CategoryName":"Alcohol","Status":true,"SubCategoryList": [{"Status":true,"SubCategoryID":5,"SubCategoryName":"Wine"}, {"Status":true,"SubCategoryID":6,"SubCategoryName":"Beer"}, {"Status":true,"SubCategoryID":7,"SubCategoryName":"Scotch"}]}, {"CategoryID":3,"CategoryName":"Restourents","Status":false,"SubCategoryList": [{"Status":true,"SubCategoryID":8,"SubCategoryName":"Breakfast"}, {"Status":true,"SubCategoryID":9,"SubCategoryName":"Tour Package"}]}]
我的代码:
JSONArray collection = new JSONArray(json1);
int length = collection.length();
for(int i=0;i<length;i++){
JSONObject row = collection.getJSONObject(i);
String value = row.getString("CategoryName");
String value6 = row.getString("SubCategoryName");
}
获取CategoryName的值:Clothing,Alcohol,Restourents
无法获取SubCategoryName的值
解析数据时出错org.json.JSONException:SubCategoryName没有值
如何获取SubCategoryName的数据。
答案 0 :(得分:0)
SubCategoryName
位于SubCategoryList jsonArray
JsonArray arr = row.getJsonArray("SubCategoryList");
arr.getJsonObject[0].getString("SubCategoryName");