Question

这是我想要获取数据的jSon数据文件，但有以下内容 -

error: 05-28 12:42:41.691: W/System.err(2887): org.json.JSONException: No value for     
vehicle_type 05-28 12:42:41.691: W/System.err(2887):    at  
 org.json.JSONObject.get(JSONObject.java:354)

 05-28 12:42:41.691: W/System.err(2887):    at   
 org.json.JSONObject.getString(JSONObject.java:510)
 05-28 12:42:41.691: W/System.err(2887):    at   
 com.example.capo.ui.MyCarActivity.returnjson(MyCarActivity.java:124)
 05-28 12:42:41.691: W/System.err(2887):    at      
 com.example.capo.net.JSONPostRequest.onPostExecute(JSONPostRequest.java:63)
 05-28 12:42:41.691: W/System.err(2887):    at     
 com.example.capo.net.JSONPostRequest.onPostExecute(JSONPostRequest.java:1)

JSON代码：

{"status":"1","records":[{"vehicle_company":"jande","vehicle_type":"751","vehicle_color":"Black","vehicle_rc":"harry1234","vehicle_capacity":"6"}],"message":"selected
> Data"}

解析JSON：

的代码

 //...
    // Parse String to JSON object
    try {

        jObj = new JSONObject(builder.toString());
        // jarray = new JSONArray(builder.toString());
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON Object
    return jObj;

}
//...

要将对象映射到的POJO Java类：公共课MyCar {

public String                                                       

 vehicle_type,vehicle_company,vehicle_color,vehicle_rc,vehicle_capacity;



  public String getVehicle_type() {
     return vehicle_type;
 }

 public void setVehicle_type(String vehicle_type) {
     this.vehicle_type = vehicle_type;
 }
 public String getVehicle_company() {
     return vehicle_company;
 }

 public void setVehicle_company(String vehicle_company) {
     this.vehicle_company = vehicle_company;
 }

 public String getVehicle_color() {
    return vehicle_color;
 }

 public void setVehicle_color(String vehicle_color) {
     this.vehicle_color = vehicle_color;
 }

 public String getVehicle_rc() {
     return vehicle_rc;
}

public void setVehicle_rc(String vehicle_rc) {
     this.vehicle_rc = vehicle_rc;
 }

 public String getVehicle_capacity() {
     return vehicle_capacity;
 }

public void setVehicle_capacity(String vehicle_capacity) {
    this.vehicle_capacity = vehicle_capacity;
 }

}

Answer 1

转到JSONLint并解析它，您会看到JSON在记录中的语法无效（缺少“”：“）：

此致：

   {
    "status": "1",
    "records[
        {
            "vehicle_company": "jande",
            "vehicle_type": "751",
            "vehicle_color": "Black",
            "vehicle_rc": "harry1234",
            "vehicle_capacity": "6"
        }
    ],
    "message": "selectedData"
   }

正确：

 {
    "status": "1",
    "records": [
        {
            "vehicle_company": "jande",
            "vehicle_type": "751",
            "vehicle_color": "Black",
            "vehicle_rc": "harry1234",
            "vehicle_capacity": "6"
        }
    ],
    "message": "selectedData"
}

Answer 2

你的json在结果数组中是错的，它会像：

"result":

Answer 3

您发布的json（我相信不是复制和粘贴错误）是错误的：

{＆＃34;状态＆＃34;：＆＃34; 1＆＃34;＆＃34;的记录 [{＆＃34; vehicle_company＆＃34;：＆＃34; jande＆＃34;＆＃34;汽车类型＆＃34;：＆＃34; 751＆＃34;＆＃34; vehicle_color＆＃34;：＆＃34;黑色＆＃34;＆＃34; vehicle_rc＆＃34;：＆＃34; harry1234＆＃34;，＆＃34; vehicle_capacity＆＃34;：＆＃34; 6＆＃34;}]，＆＃34;消息＆＃34;：＆＃34;选择数据＆＃34;}

应该（格式化）：

{ "status":"1", "records":[ { "vehicle_company":"jande", "vehicle_type":"751", "vehicle_color":"Black", "vehicle_rc":"harry1234", "vehicle_capacity":"6" } ], "message":"selected Data" }

Answer 4

好的，我建议你转储数组中包含的对象＆＃34;记录＆＃34;然后父亲反对：

jObj = new JSONObject(builder.toString());
Log.v("JSON Parser", "jObj:"+jObj);
Log.v("JSON Parser", "array:"+jObj.getJSONArray("records"));
JSONObject elem = jObj.getJSONArray("records").getJSONObject(0);
Log.v("JSON Parser", "obj:"+elem);

看看会出现什么......

获取JSON数据错误

4 个答案: