嗨，有男人和女孩，
所以我对Python相对较新（现在已经学习了大约2周）并且为了加强我的学习，我一直在努力建立自己的经典地下城/冒险游戏。游戏中有一个玩家，一个怪物（将来我希望包含5个或6个），一个钥匙和一个门。玩家必须首先搜索地牢，找到钥匙，然后找到门。此外，玩家可以拿起武器并攻击/躲避怪物。
如果玩家进入一个怪物所在的房间，那么这就会“唤醒怪物”并且它会开始追逐玩家，每回合都会靠近玩家。
我通过基于包含100个元组的列表（对于10 x 10 x-y坐标网格）打印出地图，在shell中构建了游戏的可视化表示。如果任何游戏元素的位置等于特定的x，y坐标，则它打印出一个代表性的数字（例如，如果玩家在第1,1点，它将在第1点打印出'X'，1而不是'_'或如果它是怪物它将是'！'）。
请参阅下文，了解当前地图的示例。方块目前很小（1个字符乘1个字符），我正在尝试将其扩展为3个字符乘3个字符（参见示例2），其中游戏元素值（如果有）打印在中心。
我遇到的问题是如何确定如何构建这些较大的方块，我很难过。随着越来越复杂/疯狂嵌套的for循环和if语句，我一直在搞错了一个多小时。想要避开这个问题，看看过去是否有人试图这样做/有任何方便的提示或建议。
提前感谢您的帮助！ ：）
乔伊
第一个脚本
def draw_map(p_loc, m_loc, prior_moves):
left_side_indices = list(range(0, 100))
del_multiple = 9
#This for loop deletes every 9th element (ie. 9, 19, 29...99) and assigns the
#existing numbers from 0 to 98 to left_side_indices. The reason why I did this was
#because the cells that are on the right side of the grid must be printed differently
#than all of the other cells.
for i in range(10):
del left_side_indices[del_multiple]
del_multiple = del_multiple + 9
non_right_wall_grid = left_side_indices
print('\n\n\n\n' + ' _' * 10)
tile = '|{}'
#unpacking the player location to x and y
x, y = p_loc
p_loc = (x, y)
#unpacking the monster location to a and b (x and y coordinates respectively)
a, b = m_loc
m_loc = (a, b)
#loops through the grid list which is a list of tuples (x, y)
for idx, cell in enumerate(grid):
if idx in non_right_wall_grid:
if cell == player_loc:
print(tile.format('X'), end="")
elif cell == monster_loc and player.spotted_monster == True:
print(tile.format('!'), end="")
elif cell == door_loc and player.spotted_door == True:
print(tile.format('O'), end="")
elif cell in prior_moves:
print(tile.format('.'), end="")
else:
print(tile.format('_'), end="")
else:
if cell == player_loc:
print(tile.format('X|'))
elif cell == monster_loc and player.spotted_monster == True:
print(tile.format('!|'))
elif cell == door_loc and player.spotted_door == True:
print(tile.format('O'))
elif cell in prior_moves:
print(tile.format('.|'))
else:
print(tile.format('_|'))
print('\n\n\n\n')
第一个脚本 - 输出
_ _ _ _ _ _ _ _ _ _
|_|_|_|_|_|_|_|_|_|_|
|_|_|_|_|_|_|_|_|_|_|
|_|_|.|.|.|.|_|_|_|_|
|_|_|_|.|_|.|_|_|_|_|
|_|_|_|.|.|O|X|_|_|_|
|_|_|_|.|_|_|_|_|_|_|
|_|_|_|.|_|_|_|_|_|_|
|_|_|_|.|_|_|_|_|_|_|
|_|_|.|.|_|_|_|_|_|_|
|_|_|_|_|_|_|_|_|_|_|
You are currently in room (7, 5).
You currently do not have the key.
You are currently able to go ['LEFT', 'RIGHT', 'UP', 'DOWN'], type the appropriate word to check out that room.
Type QUIT to stop playing DUNGEON or HELP for help.
Player: (7, 5)
Monster: (2, 7)
Door: (6, 5)
Key: (9, 1)
Moves After Spotting: 0
下面的第二个脚本（这是我最终要努力建立的）
第二个脚本
print('\n\n ___' + '___' * 18 + '__ ')
for _ in range(10):
print('| ' * 10 + '|')
print('| {} '.format('X') * 10 + '|')
print('|_____' * 10 + '|')
print('\n\n')
第二个脚本 - 输出
___________________________________________________________
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
| | | | | | | | | | |
| X | X | X | X | X | X | X | X | X | X |
|_____|_____|_____|_____|_____|_____|_____|_____|_____|_____|
解
def draw_map():
left_side_indices = list(range(0, 100))
del_multiple = 9
#This for loop deletes every 9th element (ie. 9, 19, 29...99) and assigns the existing numbers from 0 to 98 to left_side_indices
for i in range(10):
del left_side_indices[del_multiple]
del_multiple = del_multiple + 9
non_right_wall_grid = left_side_indices
print('\n\n ___' + '___' * 18 + '__ ')
for row in range(10):
print('| ' * 10 + '|')
for column in range(10):
if column in non_right_wall_grid:
print('| {} '.format(tile_contents(player_loc, monster_loc, prior_moves, row, column)), end='')
else:
print('| {} |'.format(tile_contents(player_loc, monster_loc, prior_moves, row, column)))
print('|_____' * 10 + '|')
print('\n\n')
def tile_contents(p_loc, m_loc, prior_moves, row, column):
x, y = p_loc
p_loc = (x, y)
a, b = m_loc
m_loc = (a, b)
coordinate = (column, row)
if coordinate == p_loc:
return('X')
elif coordinate == m_loc and player.spotted_monster == True:
return('!')
elif coordinate == door_loc and player.spotted_door == True:
return('O')
elif coordinate in prior_moves:
return('.')
else:
return('_')
答案 0 :(得分：1)
如下：
def print_map():
print('\n\n ___' + '___' * 18 + '__ ')
for row in range(10):
print('| ' * 10 + '|')
for column in range(10):
print('| {} '.format(tile_contents(row, column)), end='')
print('|')
print('|_____' * 10 + '|')
print('\n\n')
def tile_contents(row,column):
# Put here all conditionals based on row, column positions of player, monsters
# Return the character to be displayed in the middle of the cell
return "X"
print_map()