jQuery随机生成div并在屏幕外删除它

时间:2014-12-27 08:37:41

标签: javascript jquery css function flappy-bird-clone

所以我几乎在我学校的家庭作业项目结束时,我只是遗漏了两件我无法想象的重要事情:

1.如何用间隙的随机位置产生管道障碍物,这样鸟就可以飞过(使用改变css的功能'管道div的右侧为间隙位置),并在管道离开屏幕底部时将其移除。 (这是一个像btw一样倒置的飞鸟游戏......)

2.第二我需要一个碰撞检测功能的帮助,所以我知道游戏何时结束(这不太重要,因为我认为我可以在解决第一个问题后解决它)

 $(document).ready(function(){
//Variables
var screenWidth = $(window).width();//Screen width
var screenHeight = $(window).height();//Screen height
var birdWidth = $("#bird").width();//bird width
var y = 0;//Background y position
var astY = 0;//Pipe position

var bird = {//bird properties
    goingLeft: false,
    goingRight: false,
    lspeed: 0,
    rspeed: 0,
    maxSpeed: 10
};

setBirdPosition(screenWidth/2 - birdWidth/2, screenHeight/1.3 - birdWidth/2);
startBackgroundMovement();
spawnPipe();


//Start move the screen
function startBackgroundMovement(){
    setInterval(function()
    {
        y+=1;
    $('body').css('background-position-y',y + 'px');
    }, 10);
}


//bird starting position
function setBirdPosition(posX, posY) {
    $("#bird").css("left", posX);
    $("#bird").css("top", posY);
    bird.position = posX;
}
 (function birdLoop() {
    if (bird.goingLeft) {
        bird.lspeed = Math.min(bird.lspeed *1.1 || 1, bird.maxSpeed);
    } else {
        bird.lspeed = Math.max(bird.lspeed - 0.5, 0);
    }
    if (bird.goingRight) {
        bird.rspeed = Math.min(bird.rspeed *1.1 || 1, bird.maxSpeed);
    } else {
        bird.rspeed = Math.max(bird.rspeed - 0.5, 0);
    }
    bird.position = bird.position + (bird.rspeed - bird.lspeed);
    $("#bird").css('left', bird.position);
    requestAnimationFrame(birdLoop);
}());

//Move bird
$(document).keydown(function(e){
    switch(e.which){
        case 37://left
            bird.goingLeft= true; 
             //left edge of screen
      if (bird.position < 0) {
        bird.position = 0;
      }
      break;
        case 39://right
            bird.goingRight= true;
             //right edge of screen
      if (bird.position > screenWidth - birdWidth) {
        bird.position = screenWidth - birdWidth;
      }
        default: return;    
    e.preventDefault();//not sure if needed
    }
}).keyup(function(e){
    switch(e.which){
        case 37://left
            bird.goingLeft= false;
            //left edge of screen
       if (bird.position < 0) {
        bird.position = 0;
      }
            break;
        case 39://right
            bird.goingRight= false;
            //right edge of screen
      if (bird.position > screenWidth - birdWidth) {
        bird.position = screenWidth - birdWidth;
      }
        default: return;    
    e.preventDefault();//not sure if needed
    }
});

function spawnPipe()//spawn pipes
{
    setInterval(function()
    {
        astY += 1;
        $("#fullPipe").css("top", astY);              
    }, 10);
}
});

请检查:http://jsfiddle.net/u38ratk9/6/

0 个答案:

没有答案