Question

我试图将这句话分开

"Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot " \
"for it. Did he mind? Adam Jones Jr. thinks he didn't. In any case, this " \
"isn't true... Well, with a probability of .9 it isn't."

进入下面的列表。

Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot for it.
Did he mind?
Adam Jones Jr. thinks he didn't.
In any case, this isn't true...
Well, with a probability of .9 it isn't.

代码：

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )[^a-z]',text)

输出：

['Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid
 a lot for it. ', "Adam Jones Jr. thinks he didn't. "]

K gud，但它错过了一些，有没有办法告诉Python，因为最后[^ a-z]不属于我的小组，请继续从那里搜索。

修改

这是通过@sputnick提到的前瞻性正则表达式实现的。

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )(?=[^a-z])',text)

输出：

['Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid
 a lot for it. ', 'Did he mind? ', "Adam Jones Jr. thinks he didn't. "
, "In any case, this isn't true... "]

但我们仍然需要最后一句话。有什么想法吗？

Answer 1

试试这个：

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )(?=[^a-z])',text)

使用正面预测正则表达式技术，检查http://www.regular-expressions.info/lookaround.html

Answer 2

(.+?)(?<=(?<![A-Z][a-z])(?<![a-z]\.[a-z])(?:\.|\?)(?=\s|$))

试试这个。参见demo.Grab捕获或分组。使用re.findall。

https://regex101.com/r/gQ3kS4/45

Answer 3

最后

 print re.findall('[A-Z]+[^.].*?[a-z.][.?!] (?=[^a-z])|.*.$',text)

以上作品根据需要完美。包括最后一句。但我不知道为什么|.*.$工作，请帮助我理解。

输出：

['Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid
 a lot for it. ', 'Did he mind? ', "Adam Jones Jr. thinks he didn't. "
, "In any case, this isn't true... ", "Well, with a probability of .9 
it isn't."]

Python正则表达式，条件搜索

3 个答案: