Question

我们可以写一个Python程序来转

2.4 Threads /35,Black,notBold,notItalic,closed,TopLeftZoom,0,0,0.0
      2.4.1 Multithreading/35,Black,notBold,notItalic,open,TopLeftZoom,0,0,0.0
          2.4.4.1 Hierarchical Design 28/39,Black,notBold,notItalic,open,TopLeftZoom,0,0,0.0

到

2.4 Threads 24/35,Black,notBold,notItalic,closed,TopLeftZoom,0,0,0.0
      2.4.1 Multithreading 24/35,Black,notBold,notItalic,open,TopLeftZoom,0,0,0.0
          2.4.4.1 Hierarchical Design 28/39,Black,notBold,notItalic,open,TopLeftZoom,0,0,0.0

要点是：

每行都有/，后跟数字和逗号。
如果/前面没有数字，请在/前添加数字减11。
如果/前面已有一个数字，那么就单独留下一行。

Answer 1

您可以使用RegEx，(\s*\d*)/(\d+)捕获/周围的数字，然后您可以根据您的条件使用自定义函数替换第一个数字，例如

def replacer(matchobj):
    if matchobj.group(1).lstrip() == "":
        return " {}/{}".format(int(matchobj.group(2)) - 11, matchobj.group(2))
    else:
        return "/".join(matchobj.groups())

print(re.sub(r"(\s*\d*)/(\d+)", replacer, data))

<强>输出

2.4 Threads 24/35,Black,notBold,notItalic,closed,TopLeftZoom,0,0,0.0
      2.4.1 Multithreading 24/35,Black,notBold,notItalic,open,TopLeftZoom,0,0,0.0
          2.4.4.1 Hierarchical Design 28/39,Black,notBold,notItalic,open,TopLeftZoom,0,0,0.0

RegEx (\s*\d*)/(\d+)表示匹配零个或多个空格后跟零个或多个数字后跟/个字符，然后是一个或多个数字。

条件字符串插入

1 个答案: