Question

我想从结果中排除可变数量的用户/ ID。有没有办法将可变数量的用户名/ id传递给IN运算符？简化代码如下： -

CREATE DEFINER=`root`@`localhost` PROCEDURE `myroutine`(@userids)
--possible process here--
BEGIN
SELECT * FROM mytable WHERE `myid` NOT IN (@useridsprocessed)
END

Answer 1

为了关闭，这是我可以开始工作的最佳答案，但它让我感到很乱。

DELIMITER $$

CREATE DEFINER=`root`@`localhost` PROCEDURE `mytable`(IN excluded VARCHAR(255))
BEGIN
SET @sql = CONCAT('SELECT * FROM entries WHERE `id` NOT IN (', excluded,')');
  PREPARE stmt FROM @sql;
  EXECUTE stmt;
  DEALLOCATE PREPARE stmt;
END

如下调用： -

SET @excluded = '\'19\',\'26\',\'27\'';
call liquidfinger.mytable(@excluded);

将Array传递给MySQL Routine IN运算符

1 个答案: