我可以正确访问我的二维数组,并更改它..
看看我的代码。
我需要使用a.getcity
并希望获得citytable[ ][ ]
我可以更改它
/////////////////////////////////////////////////////////////////////////
bool checkcol_big(int fromA, int toB, int fromC,char city[][11]){
for (int i = fromA; i < toB; i++){
if (city[fromC][i] == 'P'){
return false;
}
}
return true;
}
bool checkrow_big(int fromA, int fromB, int fromC,char city[][11]){
for (int i = fromA; i <fromB; i++){
if (city[i][fromC] == 'P'){
return false;
}
}
return true;
}
void changecity(char city[11][11], int changerow, int changecol, int taxi)
{
if (taxi == 1)
city[changerow][changecol] = 'T1';
else
city[changerow][changecol] = 'T2';
}
Orgnizer::Orgnizer(const Taxi &taxi1, const Taxi &taxi2, City &a, Simulation &sim){
if (sim.getOpp() == 1 || sim.getOpp() == 2)
{
if (sim.getFromcol() < sim.getTocol()){
if (checkcol_big(sim.getFromcol(), sim.getTocol(), sim.getFromrow(), a.getCity)){
if (sim.getFromrow() > sim.getTorow()){
if (checkrow_big(sim.getFromrow(), sim.getTorow(), sim.getTocol(), a.getCity)){
//a[sim.getTorow][sim.getTocol] == 'T1';
changecity(a.getCity, sim.getTorow(), sim.getTocol(), sim.getNumtaxi());
//a[sim.getTorow][sim.getTocol] == 'T2';
}
}
}
}
}
}
void City::setCity(char x[][11])
citytable[11][11] = x[11][11];
}
char City::getCity() const
{
return citytable[11][11];
}
答案 0 :(得分:0)
char* City::getCity(int x, int y)
{
return &citytable[x][y];
}
可以这样工作。
char * to_change = getCity(x,y);
*to_change = new_value;