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我正在使用XSLT将我的所有Decimal类型节点格式化为XML格式的欧洲格式。我的XML看起来像是

<?xml version="1.0" encoding="utf-16"?>
<Envelope>
  <Body>
    <getPriceRecommendationResponse>
      <status>
        <statusCode>Success</statusCode>
      </status>
      <priceRecommendation>
        <tssArticleNumber>Item Number</tssArticleNumber>
        <compoundCode>T46N</compoundCode>
        <compoundGroupCodeBucket>A</compoundGroupCodeBucket>
        <compoundCodeBucket>T46 &amp; others</compoundCodeBucket>
        <qualityIndexCode>-</qualityIndexCode>
        <qualityIndexBucket>Std Quality</qualityIndexBucket>
        <weight>66.0341</weight>
        <weightGroupBucket>BT 36.2227 and 73.4214</weightGroupBucket>
        <weightIsValidBucket>YES</weightIsValidBucket>
        <subGroupCode>PT</subGroupCode>
        <subGroupCodeBucket>7:B03</subGroupCodeBucket>
        <stockDistinction>MTS</stockDistinction>
        <productIdBucket>Item</productIdBucket>
        <referencePrice>41.9176</referencePrice>
        <averageQuantity>5</averageQuantity>
        <quantityAdjustments>0.77</quantityAdjustments>
        <highDV>2.05792</highDV>
        <averageDV>1.40269</averageDV>
        <lowDV>0.95137</lowDV>
        <additionalAdjustmentsTotal>1</additionalAdjustmentsTotal>
        <highPrice>66.42256189184</highPrice>
        <averagePrice>45.27399672488</averagePrice>
        <lowPrice>30.70694327624</lowPrice>
      </priceRecommendation>
    </getPriceRecommendationResponse>
  </Body>
</Envelope>

我的XSLT如下所示

<?xml-stylesheet type="text/xsl" href="decimalformat.xsl"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:msxml="urn:schemas-microsoft-com:xslt">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>
<xsl:decimal-format name="eu" decimal-separator=',' grouping-separator='.' />
<xsl:template match="*[number()=number()]">
    <xsl:copy>
        <xsl:value-of select="format-number(@*|node(), '#.##0,##########', 'eu')" />
    </xsl:copy> 
</xsl:template>
</xsl:stylesheet>

但是我在我的应用程序中尝试这个时遇到错误，而它在转换工具中运行良好。错误如下。

Microsoft Dynamics NAV

对System.Xml.Xsl.XslTransform.Load的调用因此消息失败：表达式必须求值为节点集。

行

如果我排除代码

<xsl:value-of select="format-number(@*|node(), '#.##0,##########', 'eu')" />

它没有给出错误但没有用。我把它改成了

<xsl:value-of select="format-number(., '#.##0,##########', 'eu')" />

也是但同样的错误。请帮我。感谢

谢谢Martin Honnen，我试过你建议的代码，仍然有同样的错误。我看过一个类似的帖子，它提供了有关我得到的错误的更多信息。 http://mikeschinkel.com/blog/gettingpastthexslterrorexpressionmustevaluatetoanodeset/#comment-484235 我认为问题是博客中提到的点

**However, if you select from a node-set but instead use </xsl:value-of> as a subelement, you get a string, and you can’t later select directly from a string.**

Answer 1

我已经尝试了http://xsltransform.net/eiZQaF6并且工作正常，样式表是

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:msxml="urn:schemas-microsoft-com:xslt">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>
<xsl:decimal-format name="eu" decimal-separator=',' grouping-separator='.' />
<xsl:template match="*[not(*) and number()=number()]">
    <xsl:copy>
        <xsl:value-of select="format-number(., '#.##0,##########', 'eu')" />
    </xsl:copy> 
</xsl:template>
</xsl:stylesheet>

结果是

<Envelope>
   <Body>
      <getPriceRecommendationResponse>
         <status>
            <statusCode>Success</statusCode>
         </status>
         <priceRecommendation>
            <tssArticleNumber>Item Number</tssArticleNumber>
            <compoundCode>T46N</compoundCode>
            <compoundGroupCodeBucket>A</compoundGroupCodeBucket>
            <compoundCodeBucket>T46 &amp; others</compoundCodeBucket>
            <qualityIndexCode>-</qualityIndexCode>
            <qualityIndexBucket>Std Quality</qualityIndexBucket>
            <weight>66,0341</weight>
            <weightGroupBucket>BT 36.2227 and 73.4214</weightGroupBucket>
            <weightIsValidBucket>YES</weightIsValidBucket>
            <subGroupCode>PT</subGroupCode>
            <subGroupCodeBucket>7:B03</subGroupCodeBucket>
            <stockDistinction>MTS</stockDistinction>
            <productIdBucket>Item</productIdBucket>
            <referencePrice>41,9176</referencePrice>
            <averageQuantity>5</averageQuantity>
            <quantityAdjustments>0,77</quantityAdjustments>
            <highDV>2,05792</highDV>
            <averageDV>1,40269</averageDV>
            <lowDV>0,95137</lowDV>
            <additionalAdjustmentsTotal>1</additionalAdjustmentsTotal>
            <highPrice>66,4225618918</highPrice>
            <averagePrice>45,2739967249</averagePrice>
            <lowPrice>30,7069432762</lowPrice>
         </priceRecommendation>
      </getPriceRecommendationResponse>
   </Body>
</Envelope>

关于XSLT的唯一奇怪的事情是领先的<?xml-stylesheet type="text/xsl" href="decimalformat.xsl"?>，如果你想使用客户端XSLT，它通常属于XML。

格式化欧洲格式的XML中的十进制类型节点时出错

1 个答案: