我需要帮助来使用选定的值创建搜索数据

时间：2014-12-21 14:42:35

标签： php

我想问一下这段代码。我有两个下拉菜单和一个按钮。我想在sql数据库中搜索我在那些下拉菜单中选择的内容。使用两个下拉菜单，sql数据库中搜索项的sql语法是什么。

这是我的数据库=测试 这是我的表

表=学生

name  |   class    |  sex   | mark |
John  |   Five     | Male   | 75
Jashi |   Four     | Female | 89   |

这是我的代码

----------
<?php
mysql_connect('localhost', 'root', '');
mysql_select_db ("test");

$whereClauses = '';
$class = count($_POST['class']);
$sex = count($_POST['sex']);
$i = 0;
if (! empty($_POST['class'])) {
foreach ($_POST['class'] as $class) {
$whereClauses .="class='".mysql_real_escape_string($class)."'";
if ($i++ == $class) {
$whereClauses .= " AND";
}
}
}
if (! empty($_POST['sex'])) {
foreach ($_POST['sex'] as $sex) {
$whereClauses .="sex='".mysql_real_escape_string($sex)."'";
}
if ($i++ == $sex) {
$whereClauses .= " AND";
}
}
$sql = "SELECT * FROM student '".$where."' ORDER BY id DESC '".$limit."'";
$result=mysql_query($sql);
while ($row = mysql_fetch_array($result)) {
echo $row['name'];
echo $row['class'];
echo $row['sex'];
echo $row['mark'];
}
?>


----------
HTML
<form action="search2.php" method="post">
<select name="class">
<option value="" selected="selected">Class</option>


</select>
<select name="sex">
<option value="" selected="selected">Sex</option>


</select>
<input type="submit" value="search" />
</form>

ANY HELP WOULD BE APPRECIATED

4 个答案:

答案 0 :(得分：0)

你可以像这个例子那样简单易行

你有类似的东西 

<form method=post>
<?php
// some fetching over here like
$id = $_GET['id']; // getting id just for example
$sql = mysql_query("SELECT FROM `somewhere` where `id`='$id'");


<select name="somename">

 while($someid = mysql_fetch_array($sql))
    {
    ?>


    <option value="<?php echo $someid['id']; ?>"><?php echo $displayname; ?></option>

    <?php } ?>
   </select>
    <input type="submit" name="sub" /></form>
    <?php 
    if(isset($_POST['sub']))
    {
    $search_id = $_POST['somename']; // value from option
    $search = mysql_query("SELECT * FROM `somewhere` WHERE `id`='$search_id'");
    // or you can use LIKE //
    // LIKE THIS //
    /*
    $search = mysql_query("SELECT * FROM `somewhere` WHERE `something` LIKE %SOMETHING%");
    */
    // Just example result down here //
    $result = mysql_fetch_array($search);
    echo '<table cellpadding="10">
    <tr>
    <th>Name</th><th>SOMETHING</tH>
    </tr>
    <tr>
    <Td>'.$result['name'].'</td><td>'.$result['something'].'</td>
    </tr>
    </table>';
    }
    ?>

答案 1 :(得分：0)

  mysql_connect('localhost', 'root', '');
  mysql_select_db ("test");

  $whereClauses = '';

   if (! empty($_POST['class'])) {
       foreach ($_POST['class'] as $class) {
        $whereClauses[] .="class='".mysql_real_escape_string($class)."'";

       }
   }
   if (! empty($_POST['sex'])) {
      foreach ($_POST['sex'] as $sex) {
      $whereClauses[] .="sex='".mysql_real_escape_string($sex)."'";
      }
   }
   $where = !empty($whereClauses) ? implode(' and ', $whereClauses) : '';
   $sql = "SELECT * FROM student '".$where."' ORDER BY id DESC '".$limit."'";
   $result=mysql_query($sql);
   while ($row = mysql_fetch_array($result)) {
        echo $row['name'];
        echo $row['class'];
        echo $row['sex'];
        echo $row['mark'];
    }

答案 2 :(得分：0)

您的解决方案就在这里，试试这个

Database Table Structure
CREATE TABLE IF NOT EXISTS `student` (
  `name` varchar(255) NOT NULL,
  `class` varchar(255) NOT NULL,
  `sex` varchar(255) NOT NULL,
  `mark` int(12) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

Insert Record
INSERT INTO `student` (`name`, `class`, `sex`, `mark`) VALUES
('John', 'Five', 'Male', 75),
('Jashi', 'Four', 'Female', 89);

<form action="" method="post">
    <select name="class">
        <option value="">-SELECT CLASS-</option>
        <option value="Four">Four</option>
        <option value="Five">Five</option>
    </select>
    <select name="sex">
        <option value="">-SELECT GENDER-</option>
        <option value="Male">Male</option>
        <option value="Female">Female</option>
    </select>
	<input type="submit" name="search" value="search" />
</form>

<?php
mysql_connect('localhost', 'root', '');
mysql_select_db ("test");
extract($_POST);
if(isset($search))
{
	if($class!='' || $sex!='')
	{
		$wh='';
		if($class!='') $wh.=" AND class='".$class."'";
		if($sex!='')   $wh.=" AND sex='".$sex."'";
		$qry=mysql_query("SELECT * FROM student where 1 ".$wh."");
		$total_record=mysql_num_rows($qry);
		if($total_record>0)
		{
			echo "<table border='1'>
					<tr>
						<td>Name</td>
						<td>Class</td>
						<td>Sex</td>
						<td>Mark</td>
					</tr>
				 ";
			while($row=mysql_fetch_array($qry))
			{
				echo "<tr>
						<td>".$row['name']."</td>
						<td>".$row['class']."</td>
						<td>".$row['sex']."</td>
						<td>".$row['mark']."</td>
					  </tr>";
			}
		}
		else
		{
			echo "No Record Found";
		}
	}
	else
	{
		echo "No Record Found";
	}
}
?>

如果您的问题得到解决，请填写正确的答案

答案 3 :(得分：0)

＆＃13;
＆＃13; 
<form action="" method="post">
    <select name="class">
        <option value="">-SELECT CLASS-</option>
        <option value="Four">Four</option>
        <option value="Five">Five</option>
    </select>
    <select name="sex">
        <option value="">-SELECT GENDER-</option>
        <option value="Male">Male</option>
        <option value="Female">Female</option>
    </select>
	<input type="submit" name="search" value="search" />
</form>

<?php
mysql_connect('localhost', 'root', '');
mysql_select_db ("test");
extract($_POST);
if(isset($search))
{
	if($class!='' || $sex!='')
	{
		$wh='';
		if($class!='') $wh.=" AND class='".$class."'";
		if($sex!='')   $wh.=" AND sex='".$sex."'";
		$qry=mysql_query("SELECT * FROM student where 1 ".$wh."");
		$total_record=mysql_num_rows($qry);
		if($total_record>0)
		{
			echo "<table border='1'>
					<tr>
						<td>Name</td>
						<td>Class</td>
						<td>Sex</td>
						<td>Mark</td>
					</tr>
				 ";
			while($row=mysql_fetch_array($qry))
			{
				echo "<tr>
						<td>".$row['name']."</td>
						<td>".$row['class']."</td>
						<td>".$row['sex']."</td>
						<td>".$row['mark']."</td>
					  </tr>";
			}
		}
		else
		{
			echo "No Record Found";
		}
	}
	else
	{
		echo "No Record Found";
	}
}
?>
＆＃13;
＆＃13;
＆＃13;

＆＃13;
＆＃13; 
<form action="" method="post">
    <select name="class">
        <option value="">-SELECT CLASS-</option>
        <option value="Four">Four</option>
        <option value="Five">Five</option>
    </select>
    <select name="sex">
        <option value="">-SELECT GENDER-</option>
        <option value="Male">Male</option>
        <option value="Female">Female</option>
    </select>
	<input type="submit" name="search" value="search" />
</form>

<?php
mysql_connect('localhost', 'root', '');
mysql_select_db ("test");
extract($_POST);
if(isset($search))
{
	if($class!='' || $sex!='')
	{
		$wh='';
		if($class!='') $wh.=" AND class='".$class."'";
		if($sex!='')   $wh.=" AND sex='".$sex."'";
		$qry=mysql_query("SELECT * FROM student where 1 ".$wh."");
		$total_record=mysql_num_rows($qry);
		if($total_record>0)
		{
			echo "<table border='1'>
					<tr>
						<td>Name</td>
						<td>Class</td>
						<td>Sex</td>
						<td>Mark</td>
					</tr>
				 ";
			while($row=mysql_fetch_array($qry))
			{
				echo "<tr>
						<td>".$row['name']."</td>
						<td>".$row['class']."</td>
						<td>".$row['sex']."</td>
						<td>".$row['mark']."</td>
					  </tr>";
			}
		}
		else
		{
			echo "No Record Found";
		}
	}
	else
	{
		echo "No Record Found";
	}
}
?>
＆＃13;
＆＃13;
＆＃13;

哇 - 什么服务！感谢PROMPT回应我的问题。你的代码工作正常。我真的很感激。感谢

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