Question

我已经走了这么远。当我运行它时，它会将字符串数字转换为浮点数，甚至为我摆脱了时间戳。那我该如何将这些数字放入新的组中？我的目标是，我希望每行成为自己的列表，但仅包含时间戳和每行的最后0之间的数字。

import pandas as pd 
import numpy as np

ver = '''
 2018.12.0400:00,0.73572,0.73614,0.73544,0.73550,520,0
2018.12.0401:00,0.73550,0.73594,0.73545,0.73553,1181,0
2018.12.0402:00,0.73553,0.73606,0.73510,0.73539,1960,0
2018.12.0403:00,0.73539,0.73621,0.73481,0.73608,2898,0


'''
number = ver.split(',')

for num in number:
    try:
        new = float(num)
        print(new)
    except:
        print('this one messed up')

Answer 1

您可以先按行拆分数据，然后再按'，'。

"myText"

输出：

ver = '''2018.12.0400:00,0.73572,0.73614,0.73544,0.73550,520,0
2018.12.0401:00,0.73550,0.73594,0.73545,0.73553,1181,0
2018.12.0402:00,0.73553,0.73606,0.73510,0.73539,1960,0
2018.12.0403:00,0.73539,0.73621,0.73481,0.73608,2898,0'''
ver = [i.split(',') for i in ver.split('\n')]

df = pd.DataFrame(ver)
df

我需要对数据分组的帮助

1 个答案: