Question

我正在努力学习C＃。我想创建一个字典，其1,8,15 ......第167个键应该是JUPITER，2,9,16 ......所以应该是MARS等。是吗可能更简单的方法吗？感谢。

     public enum Planets : int { JUPITER = 1, MARS, SUN, VENUS, MERCURY, MOON, SATURN }
     Dictionary<int, string> Dict = new Dictionary<int, string>();

     for (int key = 1; key < 169; key++)
        {
            if (key % 7 == 1)
            {
                Dict.Add(key, Planet.JUPITER.ToString());
            }
            else if (key % 7 == 2)
            {
                Dict.Add(key, Planet.MARS.ToString());
            }
            else if (key % 7 == 3)
            {
                Dict.Add(key, Planet.SUN.ToString());
            }
            else if (key % 7 == 4)
            {
                Dict.Add(key, Planet.VENUS.ToString());
            }
            else if (key % 7 == 5)
            {
                Dict.Add(key, Planet.MERCURY.ToString());
            }
            else if (key % 7 == 6)
            {
                Dict.Add(key, Planet.MOON.ToString());
            }
            else
            {
                Dict.Add(key, Planet.SATURN.ToString());
            }

Answer 1

如何在7中按for增加并使用Add中的偏移：

 for (int key = 1; key < 169; key += 7)
 {
        Dict.Add(key + 0, Planet.JUPITER.ToString());
        Dict.Add(key + 1, Planet.MARS.ToString());
        Dict.Add(key + 2, Planet.SUN.ToString());
        Dict.Add(key + 3, Planet.VENUS.ToString());
        Dict.Add(key + 4, Planet.MERCURY.ToString());
        Dict.Add(key + 5, Planet.MOON.ToString());
        Dict.Add(key + 6, Planet.SATURN.ToString());
 }

或仅使用key++并一直运行直到您满意为止：

 int key = 1;
 while ( key < 169 )
 {
        Dict.Add(key++, Planet.JUPITER.ToString());
        Dict.Add(key++, Planet.MARS.ToString());
        Dict.Add(key++, Planet.SUN.ToString());
        Dict.Add(key++, Planet.VENUS.ToString());
        Dict.Add(key++, Planet.MERCURY.ToString());
        Dict.Add(key++, Planet.MOON.ToString());
        Dict.Add(key++, Planet.SATURN.ToString());
 }

旋转和平冥王星。

如何使用基于特定条件的条目填充Dictionary对象？

1 个答案: