Question

我试图让我的代码检查我的Tic Tac Toe游戏的胜利和关系。到目前为止，胜利检查仅适用于对角线，但它仍然有问题。领带检查根本不起作用。我需要关于我的winCheck方法的帮助，并让它检查横跨，垂直和对角线的胜利。我还需要帮助才能打印出赢得比赛的玩家。这是我的代码。

import java.util.Scanner;
import java.util.StringTokenizer;

public class TicTacToe {
public static void main(String[] args){

    Scanner console = new Scanner(System.in);
    System.out.print("Enter board size (e.g. 5): ");
    int size = 0;
    if(console.hasNextInt()){   //If the console has an integer, sets the size
        size = console.nextInt();
    } else {
        while(!console.hasNextInt()){   //If no integer
            console.next(); //Discards bad input
            System.out.print("Invalid input. Enter a whole positive integer: ");
        }
        size = console.nextInt();   //Sets integer once valid input is entered
    }

    int[][] array = new int[size][size];    //Sets the board size by the input (input x input)
    int i=0;    //Initializing "i" for the loops

    do{
        i=1;    //Resets "i" to one
        for(; i<=2; i++){   //For loop repeating for both players 1 and 2
            System.out.print("Player " + i + "'s Move (row,column): ");
            String plyrInput = console.next();
            //errorCheck(plyrInput, console);
            inputParse(plyrInput, i, array);    //Sends player's coordinates, player number, and the array
            if(winCheck(array, i)==true){
                System.out.print("Game over.");
                break;
            }
        }

    }while(winCheck(array, i)==false);
    console.close();
}

public static String errorCheck(String input, Scanner console){
    while(!input.contains(",")){
        console.next();
        System.out.print("Please re-enter in proper format; row,column: ");
    }
    return console.next();
}



public static void inputParse(String input, int player, int[][] array){
    StringTokenizer tokens = new StringTokenizer(input, ",");   //Parses input by comma

    String row = tokens.nextToken();    //First part of input
    String column = tokens.nextToken(); //Second part of input

    int rowNum = Integer.parseInt(row)-1;   //Decreases the inputs by one for the array
    int colNum = Integer.parseInt(column)-1;

    //System.out.println(rowNum);
    //System.out.println(colNum);

    if(player==1){  //If the player is player one, INCREASES the array location by 1
        ++array[rowNum][colNum];
    } else {        //If the player is player two, DECREASES the array location by 1
        --array[rowNum][colNum];
    }


    for(int x=0; x<array[0].length; x++){
        for(int y=0; y<array.length; y++){
            System.out.print(array[x][y]);
        }
        System.out.println();
    }

    boardPrint(array);
}

public static void boardPrint(int[][] array){
    System.out.print("+");
    for(int size=0; size<array.length; size++){ //Prints the "+-+-+-+" part of board according to given size
        System.out.print("-+");
    }
    System.out.println();

    for(int row=0; row<array[0].length; row++){
        for(int column=0; column<array.length; column++){
            System.out.print("|");
            if(array[row][column]==1){  //If the array index has 1, prints out "X" (for player 1)
                System.out.print("X");
            } else if(array[row][column]==-1){  //If negative 1, prints out "O" (for player 2)
                System.out.print("O");
            } else {    
                System.out.print(" ");  //Otherwise if array something else, prints out a regular space
            }
        }
        System.out.println("|");

        System.out.print("+");
        for(int size=0; size<array.length; size++){
            System.out.print("-+");
        }
        System.out.println();
    }
}

public static boolean winCheck(int[][] array, int player){
    int counter = 1;
    for(int i=0; i<array.length-1; i++){
        if(array[i][i] == array[i+1][i+1]){
            counter++;
        }
        if(counter==array.length){
            System.out.println("Player " + player + " wins.");
            return true;
        }
    }
    System.out.println(counter);
    return false;
}
}

Answer 1

这看起来像是一个练习，所以我只是给出一个答案的大纲。但是如果你想简化检查逻辑，我会写一个类似于

的方法

static boolean checkLine(int[][] array, int startRow, int startCol, int rowIncrement, int colIncrement) { 
    ...
}

如果数组的一条直线上的所有内容相等（而不是空方格），则返回true，否则返回false。对于您已编码的对角线，您需要调用

win = checkLine(array, 0, 0, 1, 1);

因为您将开始查看array[0][0]，并且您检查的每个方格将位于比前一行更多的第1行，而第1列比前一列更多（因此{{1} }，array[1][1]）。

要查看底行，您要查看array[2][2]，array[2][0]，array[2][1]的位置，您可以这样称呼它：

array[2][2]

表示从第2行和第0列开始，然后检查其他方块，在行号中加0（因为你停留在同一行），列号为1。

您可以了解如何为每行，每列和对角线执行此操作。你打电话win = checkLine(array, 2, 0, 0, 1); 8次（3行，3列，2个对角线）。

Win / Tie检查Java中的Tic Tac Toe

1 个答案: