Question

几天前我在SQL Server中处理了一个存储过程。我创建了这个存储过程代码：

ALTER procedure [dbo].[GetEmployeeHours]  
  (@CurrentDate datetime)
as
begin
   declare @StartDate datetime
   declare @EndDate datetime

   set @StartDate = DATEADD(DAY, 1 - DATEPART(WEEKDAY, @CurrentDate), CAST(@CurrentDate AS DATE))
   set @EndDate = DATEADD(DAY, 7 - DATEPART(WEEKDAY, @CurrentDate), CAST(@CurrentDate AS DATE))
   --select @StartDate
   --select @EndDate

   SELECT
     CASE WHEN
      GROUPING(a.firstname +' '+a.lastname)=1 
      THEN 'Total By Day' 
      ELSE 
      a.firstname +' '+a.lastname
       END AS [EmployeeName] ,
    SUM(CASE WHEN datename(dw,workdate)='Monday' THEN [hours] ELSE 0 END) AS Monday,
    SUM(CASE WHEN datename(dw,workdate)='Tuesday' THEN [hours] ELSE 0 END) as Tuesday,
    SUM(CASE WHEN datename(dw,workdate)='Wednesday' THEN [hours] ELSE 0 END) as WEDNESDAY,
    SUM(CASE WHEN datename(dw,workdate)='Thursday' THEN [hours] ELSE 0 END) as THURSDAY,
    SUM(CASE WHEN datename(dw,workdate)='Friday' THEN [hours] ELSE 0 END) as FRIDAY,
    SUM(CASE WHEN datename(dw,workdate)='Saturday' THEN [hours] ELSE 0 END) as SATURDAY,
    SUM(CASE WHEN datename(dw,workdate)='Sunday' THEN [hours] ELSE 0 END) as SUNDAY,
    SUM(hours) AS [TotalHours]
FROM Project_TimeSheet b  inner join Project_Employee a on b.employeeid =a.id
WHERE workdate >= @StartDate and workdate<= @EndDate
GROUP BY a.firstname +' '+a.lastname 
WITH ROLLUP
end

在这个存储过程中，我得到每天的结果，并将周名称作为列名。首先，我想使用数据透视表，但我在堆栈溢出时发现了这一点，所以我使用它。现在我想在星期名称的位置显示日期作为列名。有人可以告诉我怎么办？我尝试通过声明变量来分配值，但所有这些都不起作用

由于

Answer 1

您需要使用动态SQL。如果您查找动态数据透视的示例，您将快速找到代码。但要注意，因为消耗结果的应用程序需要足够聪明才能发现列名...

如何在SQL Server表中将日期显示为列名

1 个答案: