Question

我的Sql表类似于下面的

Code  Value  ID
A     100    1
A     200    2
A     300    3
B     200    1
B     500    2
B     600    3
C     800    1 
C     700    2
C     200    3

如何在sql server 2008中编写查询以获取以下格式的值。

ID A    B    C
1  100  200  800
2  200  500  700
3  300  600  200

Answer 1

您可以使用SUM功能：

SELECT ID,
        SUM(CASE Code when 'A' then Value else 0 end)as A,
        SUM(CASE Code when 'B' then Value else 0 end)as B,
        SUM(CASE Code when 'C' then Value else 0 end)as C
FROM myTable
GROUP BY ID;

See this SQLFiddle

Answer 2

使用PIVOT

select ID,[A],[B],[C]
from your_table T
PIVOT (MAX(Value) FOR Code in ([A],[B],[C]) )P

如果代码未修复，则可以使用动态支点

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT distinct ',' + QUOTENAME(Code) 
                    from your_table
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT ID,  ' + @cols + '  
                from your_table
            pivot 
            (
                MAX([Value])
                for Code in (' + @cols + ')
            ) p '
print(@query)
execute(@query)

Answer 3

答案是PIVOT

DECLARE @t TABLE (Code varchar(10), Value int, Id int)

INSERT INTO @t VALUES
                    ('A',100,1),
                    ('A',200,2),
                    ('A',300,3),
                    ('B',200,1),
                    ('B',500,2),
                    ('B',600,3),
                    ('C',800,1),
                    ('C',700,2),
                    ('C',200,3);

SELECT ID,[A],[B],[C]
FROM @t
PIVOT (SUM(Value) FOR Code IN ([A],[B],[C]))P

<强>结果

ID  A   B   C
1   100 200 800
2   200 500 700
3   300 600 200

如何将查询表值写为列名？

3 个答案: