我有一个问题，也许是愚蠢的，我写的代码。我生成了30个24行的数据集，其中包含不同的值，但这些数据表示相同的度量，但我无法以数组格式打印它们。让我解释一下，我得到一个包含所有值的列，我可以将它们写成24行乘30列的矩阵。我尝试在这个网站和其他网站上阅读各种线程，但我的零值矩阵与我的价值观交替，我该怎么办？以下是我写的代码，试图获得矩阵＆＃34; a＆＃34;由＆＃34; diffu＆＃34;
的值组成program deviation
implicit none
character(len=20) :: filein,fileout,fileinp
integer :: row,i,h,io,n,j,l,m,col
real :: usv,usf,tsv,tsf,su,st
real :: diffu, difft
real, dimension(24,30) :: a
real, dimension(720) :: u
n = 39
row = 24
col = n-9
write(*,'(2x,''Input file .......''/)')
read(*,'(a15)') filein
write(*,'(2x,''Output file........''/)')
read(*,'(a15)') fileout
open(unit = 20,File=fileout)
a = 0.
fileLoop : do i = 10,n
fileinp = 'lin*27-'
write(fileinp, '("lin*27-",I2,".dat")') i
open(unit = i+40,File=fileinp)
open(unit = 30,File=filein)
do j = 1, row
read(30,*,IOSTAT = io) h,usv,tsv
read(i+40,*,IOSTAT = io) h,usf,tsf
if(io/=0) then
write(*,*) 'End of file!'
exit
else if(io==0) then
diffu = ((usf - usv)**2)
difft = ((tsf - tsv)**2)
write(20,*) diffu,difft
endif
enddo
enddo
close(i+40)
close(30)
enddo fileLoop
close(20)
open(unit=20,STATUS='OLD',FILE=fileout)
do r = 1, 720
read(20,*,IOSTAT = io) diffu,difft
u(r) = diffu
if(io/=0) then
write(*,*) "Error!"
exit
else if(io==0) then
do m = 1, 24
do l = 1, col
a(m,l) = a(m,l) + u(r)
enddo
enddo
endif
enddo
write(*,*) a
close(20)
end program deviation