离开范围时析构函数调用的顺序？ （C ++）

Question

我试图理解退出范围时析构函数调用的顺序。假设我有以下代码：

class Parent{

Parent(){cout<<"parent c called \n";}
~Parent(){cout<< "parent d called \n";}
};

class Child: public parent{

Child(){cout<< "child c called \n";}
~Child(){cout<<"child d called\n";}
};

现在，我知道子构造函数和析构函数是从父类派生的，所以主要是：

int main(){

Parent Man;
Child Boy;

return 0;
}

会产生输出：

parent c called
parent c called
child c called
... //Now what?

但现在，当我退出范围时会发生什么？我有很多需要销毁的东西，那么编译器如何选择订单呢？我可以有两种输出可能性：

parent c called           |         parent c called      
parent c called           |         parent c called
child c called            |         child c called
child d called            |         parent d called
parent d called           |         child d called
parent d called           |         parent d called

如果首先销毁Boy，则应用左侧案例，如果首先销毁Man，则应用右侧案例。计算机如何决定首先删除哪一个？

Answer 1

在祖先析构函数之前调用派生的析构函数。因此，首先调用Child析构函数体，然后调用Parent析构函数体。并且构造的对象以相反的顺序被破坏，因此Boy对象将在Man对象被破坏之前被破坏。