Question

这个程序正在努力分离负数，奇数和偶数整数。编译时，它会向用户询问2个数字而不是1个数字，然后中断。如何通过要求2个数字来修复它。

import java.util.Scanner;
import java.util.Arrays;

public class Integer{
public static void main(String [] args){
    Scanner reader = new Scanner (System.in);

    double number;  
    int count = 0;
    double [] evenList = new double[count];
    double [] oddList = new double[count];
    double [] negativeList = new double[count];

    for (int i = 0; i < 10; i++){
        System.out.println("Please enter an integer: ");
        number = reader.nextDouble();
        count++; 

        if (number < 0) {
            negativeList[i] = reader.nextDouble();
        }
        if (number % 2 == 0) {
            evenList[i] = reader.nextDouble();
        } else {
            oddList[i] = reader.nextDouble();
        }     
    }

    System.out.println("Negatives: " + Arrays.toString(negativeList));
    System.out.println("Odds: " + Arrays.toString(oddList));
    System.out.println("Evens: " + Arrays.toString(evenList));
}
}

Answer 1

您正在if块内的扫描仪再次读取值。请改用number

    if (number < 0) {
        negativeList[i] = number;
    }
    if (number % 2 == 0) {
        evenList[i] = number;
    } else {
        oddList[i] = number;
    }

Answer 2

改变这个：

if ( number < 0 ) {
    negativeList [ i ] = reader . nextDouble ( ) ;
}

if ( number % 2 == 0 ) {
    evenList [ i ] = reader . nextDouble ( ) ;
} 
else {
    oddList [ i ] = reader . nextDouble ( ) ;
}

到此：

if ( number < 0 ) {
    negativeList [ i ] = number ;
}

if ( number % 2 == 0 ) {
    evenList [ i ] = number ;
} 
else {
    oddList [ i ] = number ;
}

Answer 3

你可能想要这个：

number = reader.nextDouble(); // read the number using Scanner once
count++; 

// use it to futher to add to respective arrays
if (number < 0) {
    negativeList[i] = number;
}
if (number % 2 == 0) {
    evenList[i] = number;
} else {
    oddList[i] = number;
}

Java要求两个数字而不是1

3 个答案: