Question

我遇到这个问题我遇到了错误。我需要写一个叫做水滴的函数画出一系列水滴。参数是t乌龟绘制液滴，尺寸（每个液滴的直径）和分离（这是一个列表，它用于每个液滴之间的距离）。我使用Python 3.4.2版。我得到的错误是TypeError。这是代码：

def droplets(t, size, separations):
    for i in range(len(separations)):
        t.down()
        t.circle(size)
        t.up()
        t.forward([separations * i])

import turtle
turt = turtle.Turtle()
droplets(turt, 5, [20, 25, 30])

错误：

Traceback (most recent call last):
  File "C:/Python34/My Python Program/Midterm 2 PP Test.py", line 10, in <module>
    droplets(turt, 5, [20, 25, 30])
  File "C:/Python34/My Python Program/Midterm 2 PP Test.py", line 6, in droplets
    t.forward([separations * i])
  File "C:\Python34\lib\turtle.py", line 1636, in forward
    self._go(distance)
  File "C:\Python34\lib\turtle.py", line 1603, in _go
    ende = self._position + self._orient * distance
  File "C:\Python34\lib\turtle.py", line 257, in __mul__
    return Vec2D(self[0]*other, self[1]*other)
TypeError: can't multiply sequence by non-int of type 'float'

Answer 1

如果您想迭代separations：

def droplets(t, size, separations):
    for i in range(len(separations)):
        t.down()
        t.circle(size)
        t.up()
        t.forward(separations[i])

或者，更简单地说，只需迭代separations而不是使用索引：

def droplets(t, size, separations):
    for separation in separations:
        t.down()
        t.circle(size)
        t.up()
        t.forward(separation)

如何解决这个龟功能？

1 个答案: