PHP多维数组 - 使其工作

时间:2014-12-11 14:56:25

标签: php function multidimensional-array

我想要做什么我不知道它的正确名称所以如果我使用了错误的术语我会道歉。

以下是我想要实现的基本示例:

$arrayData = (4,5,6,7,8,9,10);

$public function setArray($colNum){
    $i = 0;
    while($i < count($arrayData){

这是我不知道该怎么做的地方。我希望$ colNum设置新数组中的列数。所以

if $colNum = 4, then $arrayNew[$i][$i][$i][$arrayData[$i]
然后将设置

。目前我已经创建了多个函数,每个函数处理不同数量的列并且可以工作,但它的范围可以从2列到30列,我知道必须有一种方法可以更有效地完成它。

这是一个4列表(代码尚未优化)的工作示例

public function parseTable($tableHeader,$isMoney,$colNum) {
    $tableData = $this->myArray;
    $count = 0;
    $placeHolder = 0;

    while($count < count($tableData)){

        // This hides the column headers
        if($count > $colNum - 1) {
            $col1Array[$placeHolder] = $tableData[$count];
            $col2Array[$placeHolder] = $tableData[$count + 1];
            $col3Array[$placeHolder] = $tableData[$count + 2];
            $col4Array[$placeHolder] = $tableData[$count + 3];
            $placeHolder ++;
        }

        $count = $count + $colNum;

    }

    // Remove the empty lines from the array
    $col1Array = array_values(array_filter($col1Array));
    $col2Array = array_values(array_filter($col2Array));
    $col3Array = array_values(array_filter($col3Array));
    $col4Array = array_values(array_filter($col4Array));

    // Put the 0 back in the array
    $col1Array = array_values(str_replace('~',0,$col1Array));
    $col2Array = array_values(str_replace('~',0,$col2Array));
    $col3Array = array_values(str_replace('~',0,$col3Array));
    $col4Array = array_values(str_replace('~',0,$col4Array));

    $count = 0;
    $tableHTML = "<table class=\"table table-striped table-hover\"  data-toggle=\"table\"
           data-search=\"true\"
           data-show-columns=\"true\"
           data-pagination=\"true\"
        >
        <thead>
            <tr>
                <th>$tableHeader[0]</th>
                <th>$tableHeader[1]</th>
                <th>$tableHeader[2]</th>
                <th>$tableHeader[3]</th>
            </tr>
        </thead>
        <tbody>";

    while($count < count($col1Array)){
        // Replaces empty values with the text set when calling the function
        if($col1Array[$count] == ""){
            $col1Array[$count] = $emptyResult;
        }
        if($col2Array[$count] == ""){
            $col2Array[$count] = $emptyResult2;
        }
        if($col3Array[$count] == ""){
            $col3Array[$count] = $emptyResult3;
        }
        if($col4Array[$count] == ""){
            $col4Array[$count] = $emptyResult4;
        }

        // Converts data into money if specified in the function
        if($isMoney[0] == "Currency"){
            if($col1Array != '0'){$colOne =  money_format('%.2n', $col1Array[$count]);}
            else{$col1Array = "$0.00";}
        }else{$colOne = str_replace('0.00','0',$col1Array[$count]);}
        if($isMoney[1] == "Currency"){
            if($col2Array != '0'){$colTwo =  money_format('%.2n', $col2Array[$count]);}
            else{$colTwo = "$0.00";}
        }else{$colTwo = str_replace('0.00','0',$col2Array[$count]);}
        if($isMoney[2] == "Currency"){
            if($col3Array != '0'){$colThree =  money_format('%.2n', $col3Array[$count]);}
            else{$colThree = "$0.00";}
        }else{$colThree = str_replace('0.00','0',$col3Array[$count]);}
        if($isMoney[3] == "Currency"){
            if($col4Array != '0'){$colFour =  money_format('%.2n', $col4Array[$count]);}
            else{$colFour = "$0.00";}
        }else{$colFour = str_replace('0.00','0',$col4Array[$count]);}

        $tableHTML = $tableHTML . "
        <tr>
            <td>$colOne</td>
            <td>$colTwo</td>
            <td>$colThree</td>
            <td>$colFour</td>
        </tr>";
        $count++;
    }

    $tableHTML = $tableHTML . "
        </tbody>
    </table>";

    $this->tableHTML = $tableHTML;
    $this->col1Array = $col1Array;
    $this->col2Array = $col2Array;
    $this->col3Array = $col3Array;
    $this->col4Array = $col4Array;
    $this->totalRows = count($this->col1Array);
}

3 个答案:

答案 0 :(得分:2)

以下是array_push:

的解决方案
$arrayData = array(4,5,6,7,8,9,10);
$setArray = function($colNum) use($arrayData) {
    $new_array = array();
    for ($i = 0; $i < $colNum; $i++){
        $old_array = array();
        array_push($new_array, $old_array);
    }
    array_push($new_array, $arrayData);
    return $new_array;
};

$new_array = $setArray(5);

echo '<pre>';
die(var_dump($new_array));

答案 1 :(得分:1)

我不确定自己能得到什么。虽然看起来确实需要使用递归函数。

例如:

$array = array();

create_multi_array($array, 10);

function create_multi_array(&$array, $dim){
    if($dim==0)
        return;
    create_multi_array($array[0], $dim-1);
}
echo "<pre>";
var_dump($array);

输出:

array(1) {
  [0]=>
  array(1) {
    [0]=>
    array(1) {
      [0]=>
      array(1) {
        [0]=>
        array(1) {
          [0]=>
          array(1) {
            [0]=>
            array(1) {
              [0]=>
              array(1) {
                [0]=>
                array(1) {
                  [0]=>
                  array(1) {
                    [0]=>
                    NULL
                  }
                }
              }
            }
          }
        }
      }
    }
  }
}

答案 2 :(得分:1)

感谢大家的帮助!我有很多我正在研究的代码,并试图尽可能小地解决我遇到的问题。我知道它可能会令人困惑,但我不想发布所有内容,因为我知道这是一个很容易修复的小问题。我一直在寻找一种在数组中存储可变数量的数组的有效方法。我的直接解决方案是为将要存储的每个数组创建函数。但是,我想要一种方法来实现1个函数可以动态地在数组中存储尽可能多的数组。这是@Sofiane Sadi代码的解决方案。

$arrayData = array(array(7,8,9),array(5,6,7),array(8,9,10));
$setArray = function($colNum) use($arrayData) {
$new_array = array();
for ($i = 0; $i < $colNum; $i++){
    $old_array = array();
}
array_push($new_array, $arrayData);
return $new_array;
};

$new_array = $setArray(2);

echo '<pre>';
die(var_dump($new_array));