我有一些问题将多维数组简化为正常数组。
我有一个像这样的输入数组:
Array
(
[0] => Array (
[0] => 17
[1] => 99
)
[1] => Array (
[0] => 17
[1] => 121
)
[2] => Array (
[0] => 99
[1] => 77
)
[3] => Array (
[0] => 45
[1] => 51
)
[4] => Array (
[0] => 45
[1] => 131
)
所以我有一个多维数组,在值中有一些重叠(例如17,99和17,121) 现在我希望有这样的输出:
Array
(
[0] => Array (
[0] => 17
[1] => 99
[2] => 121
[3] => 77
)
[2] => Array (
[0] => 45
[1] => 51
[3] => 131
)
我想保存,这样在我的数据库中哪些文章是相同的。输出数组shpuld仍然是一个多维数组,但第二级的每个数字在数组中都应该是唯一的。
我现在试图解决这个问题一个多星期了,但是我没有让它发挥作用。我知道它应该很容易......但无论如何 - 我不明白:D
这是我到目前为止所得到的:
$parity_sorted = array();
foreach($arr as $key => $a){
if(count($parity_sorted) > 0){
foreach($parity_sorted as $key2 => $arr_new){
if(in_array($a[0], $arr_new) || in_array($a[1], $arr_new)){
if(!in_array($a[0], $arr_new)){array_push($parity_sorted[$key2], $a[0]);}
if(!in_array($a[1], $arr_new)){array_push($parity_sorted[$key2], $a[1]);}
} else {
array_push($parity_sorted, array($a[0],$a[1]));
}
}
} else {
array_push($parity_sorted, array($a[0],$a[1]));
}
}
您是否已经解决过这样的问题或者有更简单的方法吗?也许我只是觉得太复杂了(这不是我的第一次尝试,但这段代码是最后一次尝试)
任何帮助将不胜感激。非常感谢
答案 0 :(得分:1)
这是我修改后的代码,给出了您的评论,并且其演示文稿按预期工作。 (http://codepad.org/CiukXctS)
<?php
$tmp = array();
foreach($array as $value)
{
// just for claraty, let's set the variables
$val1 = $value[0];
$val2 = $value[1];
$found = false;
foreach($tmp as &$v)
{
// check all existing tmp for one that matches
if(in_array($val1, $v) OR in_array($val2, $v))
{
// this one found a match, add and stop
$v[] = $val1;
$v[] = $val2;
// set the flag
$found = true;
break;
}
}
unset($v);
// check if this set was found
if( ! $found)
{
// this variable is new, set both
$tmp[] = array(
$val1,
$val2,
);
}
}
// go trough it all again to ensure uniqueness
$array = array();
foreach($tmp as $value)
{
$array[] = array_unique($value); // this will eliminate the duplicates from $val2
}
ORIGIN ANSWER
问题很严重,但我会尝试回答我认为的问题。
您想收集对中具有相同第一个值的所有数组对吗?
$tmp = array();
for($array as $value)
{
// just for claraty, let's set the variables
$val1 = $value[0];
$val2 = $value[1];
if(isset($tmp[$val1])) // we already found it
{
$tmp[$val1][] = $val2; // only set the second one
}
else
{
// this variable is new, set both
$tmp[$val1] = array(
$val1,
$val2,
);
}
}
// go trough it all again to change the index to being 0-1-2-3-4....
$array = array();
foreach($tmp as $value)
{
$array[] = array_unique($value); // this will eliminate the duplicates from $val2
}
答案 1 :(得分:0)
这是常见任务的解决方案。
$data = array(array(17,99), array(17,121), array(99,77), array(45,51), array(45,131));
$result = array();
foreach ($data as $innner_array) {
$intersect_array = array();
foreach ($result as $key => $result_inner_array) {
$intersect_array = array_intersect($innner_array, $result_inner_array);
}
if (empty($intersect_array)) {
$result[] = $innner_array;
} else {
$result[$key] = array_unique(array_merge($innner_array, $result_inner_array));
}
}
var_dump($result);
答案 2 :(得分:0)
尝试:
$arr = array(array(17,99),
array(17,121),
array(99,77),
array(45, 51),
array(45, 131)
);
foreach($arr as $v)
foreach($v as $m)
$new_arr[] = $m;
$array = array_chunk(array_unique($new_arr), 4);
var_dump($array);
Demo
它使用array_unique
和array_chunk
。
<强>输出:强>
array(2) { [0]=>array(4) { [0]=> int(17) [1]=>int(99)
[2]=>int(121) [3]=> int(77) }
[1]=> array(3) { [0]=> int(45) [1]=>int(51)
[2]=>int(131) }
}
答案 3 :(得分:0)
我想我得到了你的问题。让我对此有所了解。
$firstElems = array();
$secondElems = array();
foreach ( $arr as $v ) {
$firstElems[ $v[0] ] = array( $v[0] );
}
foreach ( $arr as $v ) {
$secondElems[ $v[1] ] = $v[0];
}
foreach ( $arr as $v ) {
if ( isset( $secondElems[ $v[0] ] ) ) {
array_push( $firstElems[ $secondElems[ $v[0] ] ], $v[1] );
}
else {
array_push( $firstElems[ $v[0] ], $v[1] );
}
}
foreach ( $firstElems as $k => $v ) {
if ( isset( $secondElems[ $k ] ) ) {
unset( $firstElems[ $k ] );
}
}
输出:
Array
(
[17] => Array
(
[0] => 17
[1] => 99
[2] => 121
[3] => 77
)
[45] => Array
(
[0] => 45
[1] => 51
[2] => 131
)
)
答案 4 :(得分:0)
(代码示例:http://codepad.org/rJNNq5Vd)
我真的相信我了解你,如果是这种情况,那么你正在寻找:
function arrangeArray($array) {
$newArray = array(array_shift($array));
for ($x = 0; $x < count($newArray); $x++) {
if (!is_array($newArray[$x])) {
unset($newArray[$x]);
return $newArray;
}
for ($i = 0; $i < count($newArray[$x]); $i++) {
foreach ($array as $key => $inArray) {
if (in_array($newArray[$x][$i], $inArray)) {
$newArray[$x] = array_unique(array_merge($newArray[$x], $inArray));
unset($array[$key]);
}
}
}
$newArray[] = array_shift($array);
}
}
将返回:
array(2) {
[0]=>
array(4) {
[0]=>
int(17)
[1]=>
int(99)
[2]=>
int(121)
[4]=>
int(77)
}
[1]=>
array(3) {
[0]=>
int(45)
[1]=>
int(51)
[3]=>
int(131)
}
}
有关:
var_dump(arrangeArray(array(
array(17,99),
array(17,121),
array(99,77),
array(45, 51),
array(45, 131),
)));
和
array(1) {
[0]=>
array(6) {
[0]=>
int(17)
[1]=>
int(99)
[2]=>
int(121)
[3]=>
int(45)
[4]=>
int(77)
[6]=>
int(51)
}
}
有关:
var_dump(arrangeArray(array(
array(17,99),
array(17,121),
array(99,77),
array(45, 51),
array(45, 17),
)));