正如标题所述,在ARC模式下,当我使用自引用定义块时(弱以避免引用周期):
...
id __weak weakSelf = self;
self.someBlock = ^(){
if (weakSelf != nil){
(do something with weakSelf...)
return NO;
}
return YES;
};
...
在dealloc中我调用块:
- (void)dealloc {
...
BOOL isNil = self.someBlock();
...
}
然后我发现isNil = YES。
当我想让dealloc中的块与self做某事时,这似乎是一个问题。
这也发生在回调函数中,我不会在这里给出一个例子。
我的解决方案是使用__unsafe_unretained而不是__weak。
但这看起来很难看。
是否有更好的方法可以避免dealloc中的自我弱?
更新了问题:即使weakSelf
没有,为什么self
会被识别?这是dealloc
的原因吗?
为清楚起见,我粘贴下面的测试代码:
#import <Foundation/Foundation.h>
@interface blockWeak : NSObject
@property (nonatomic, strong) BOOL (^someBlock)();
@property (nonatomic) int num;
- (void)makeBlock;
@end
@implementation blockWeak
- (void)makeBlock
{
typeof(self) __weak weakSelf = self;
self.someBlock = ^(){
typeof(self) strongSelf = weakSelf;
strongSelf.num = 2;
return weakSelf == nil?YES:NO;
};
}
- (void)dealloc
{
BOOL isNil = self.someBlock();
if (isNil) {
NSLog(@"weakSelf is nil.");
}
}
@end
int main(int argc, const char * argv[])
{
@autoreleasepool {
blockWeak *bw = [[blockWeak alloc] init];
bw.num = 1;
[bw makeBlock];
}
return 0;
}
答案 0 :(得分:1)
你不要打电话给那个街区。那将是:
BOOL isNil = self.someBlock();
答案 1 :(得分:1)
以下是有效的,在我看来更清晰,因为暂不提及self
。
此外,现在没有真正需要返回块BOOL
,但我已将其留在...
#import <Foundation/Foundation.h>
@interface blockWeak : NSObject
@property (nonatomic, copy) BOOL (^someBlock)(blockWeak *);
@property (nonatomic) int num;
- (void)makeBlock;
@end
@implementation blockWeak
- (void)makeBlock
{
self.someBlock = ^BOOL(blockWeak *object){
object.num = 2;
return object == nil?YES:NO;
};
}
- (void)dealloc
{
NSLog(@"num = %d", _num);
BOOL isNil = _someBlock(self);
if (isNil) {
NSLog(@"block returned NO");
} else {
NSLog(@"block returned YES");
}
NSLog(@"num = %d", _num);
}
@end
int main(int argc, const char * argv[])
{
@autoreleasepool {
blockWeak *bw = [[blockWeak alloc] init];
bw.num = 1;
[bw makeBlock];
}
return 0;
}
<强>输出强>:
num = 1
block returned YES
num = 2