Question

我试图制作一个基于文本的刽子手游戏。我有两个清单：

一个存储在其中的单词
一个显示＆＃39; *＆＃39;替换其他名单中的字母。

我可以检查第一个列表中的单词并替换它，只有在有一次出现时才会替换它。

例如：这个词是＆＃39; DEAD＆＃39;并且用户输入D.输出将是D ***，因为它只找到一个。

从一个列表替换到另一个列表的当前代码：

if guess() == True:
    pos = word.index(guessed)
    display[pos] = word[pos]
    print('Correct:  ', display)

如何更改代码以便替换列表中的每个匹配项？

Answer 1

您可以使用zip来逐字母地比较当前完成的字符串的答案。然后在join中使用生成器表达式来检查字母是否正确，否则不要更改它。您仍然需要添加逻辑来跟踪他们是如何被绞死的。

answer = 'dictionary'
current = '*'*len(answer)   # Produces '**********'

while current != answer:
    guess = input('guess a letter: ')
    current = ''.join(guess if guess == letter else blank for blank, letter in zip(current, answer))
    print(current, '\n')

测试

guess a letter: i
*i**i*****

guess a letter: d
di**i*****

guess a letter: c
dic*i*****

guess a letter: t
dicti*****

guess a letter: n
dicti*n***

guess a letter: l  # Note this letter was wrong so the word didn't change
dicti*n***

guess a letter: o
diction***

guess a letter: r
diction*r*

guess a letter: a
dictionar*

guess a letter: y
dictionary

Answer 2

word = "DEAD"

inp = "D"

print("".join([s if inp  == s else "_" for s in word]))
D__D

你也应该使用if guess() if guess() == True，如果guess（）在返回布尔值时为True或False。

如果您正在使用功能：

secret_word = "DEAD"


def is_guessed(secret_word, letters_guessed):
    return all(x in letters_guessed for x in secret_word)


def get_guessed_word(secret_word, guessed):
    return "".join([letter if letter in guessed else "_" for letter in secret_word])

letters_guessed = set()

guess = ""
lives = 5
while True:
    if is_guessed(secret_word,letters_guessed):
        print("Congratulations you guessed {}.".format(secret_word))
        break
    elif lives == 0:
        print("Out of lives the word was {}.".format(secret_word))
        break
    print("You have {} lives remaining".format(lives))
    inp = input("Enter a letter ").upper()
    if inp in letters_guessed:
        print("Already picked that letter")
        continue
    letters_guessed.add(inp)
    if inp.lower() in secret_word:
        print("Good guess")
        print(get_guessed_word(secret_word, letters_guessed))
    else:
        print("{} is not in the word".format(inp))
        lives -= 1

Answer 3

word = "dead" 
right_answer = set() #1

def replace_star(): # this part is relevant to your quesiton
    uncoverd = "" # first it makes a empty string
    for char in word: # loops trough every character in the word
        if char in right_answer: # if the character is in the set of right_answers
            uncoverd += char # it adds the character to the empty string
        else: # if is not 
            uncoverd += "*" # it add a '*'
    return uncoverd # returns the new word with all the character replaced with eiter a '*' or the guesses right character

score = 10
while True:
    uncoverd = replace_star()
    print ("Word:",uncoverd)
    answer = input("Guess one character of the word.\n>>")
    if answer in word: # 2
        print ("Spot on!")
        right_answer.add(answer) # 3
        if right_answer == set(word): # 4
            print ("You Win!")
            print ("The word was:", word)
            break
    else:
        score -= 1
        print ("Wrong")
        print ("Score: '%s'"%score)
        if score == 0:
            print ("You Lose!")
            break

通过使用set，您可以检查序列中的所有唯一项是否存在于另一个

中

你创建一个空集
检查用户输入字符是否在word
将此字符添加到right_answer集
检查right_answer是否等于单词中的字符集。

如何用另一个值替换列表中的每个值？

3 个答案: