Question

想生成报告，其中计算天数，物料在仓库中。天数是材料进入的日期($3 field)之间的差异生成报告的日期(05-NOV-2014)以查看广告资源。现在，我该如何解决这个问题。而且，一旦我得到天数，这些必须归类为

CAT-1 for the days 0-30Days,CAT-2 for days 31-60Days,CAT-3 for days 61-90Days,CAT-4 for days 91-180Days,
CAT-5 for days 181-365Days,CAT-6 for days 365-730Days,CAT-7 for days Greaterthan>730Days

反对Product($4) and Material($5)明智的组合。

Input.csv

Des11,Des22,DateIn,Product,Material,Loc11,Loc22

10,a,15-SEP-14.11:09:06,ab,pq,yyy,zzz
20,a,23-SEP-14.08:09:35,ab,pq,yyy,zzz
10,a,15-MAY-14.08:09:26,ab,pq,yyy,zzz
62,a,17-FEB-12.03:09:23,ab,pq,yyy,zzz
10,a,04-NOV-14.11:09:06,cd,rs,yyy,zzz
20,a,12-AUG-14.08:09:35,cd,rs,yyy,zzz
10,a,16-DEC-13.08:09:26,cd,rs,yyy,zzz
62,a,18-DEC-13.03:09:23,cd,rs,yyy,zzz

例如，我手动调整Aging桶如下：报告生成日期是手动输入，因此我可以使用任何格式，如05-Nov-14或05-NOV-2014或20141105 但是，我没有权利改变输入的输入，即15-SEP-14.11：09：06

DateofReportGen,DateIn($3),DateIn,NoOfDays,Ageing Bucket
05-Nov-14,15-SEP-14.11:09:06,15-Sep-14,51,31-60Days
05-Nov-14,23-SEP-14.08:09:35,23-Sep-14,43,31-60Days
05-Nov-14,15-MAY-14.08:09:26,15-May-14,174,91-180Days
05-Nov-14,17-FEB-12.03:09:23,17-Feb-12,992,Greaterthan>730Days
05-Nov-14,04-NOV-14.11:09:06,04-Nov-14,1,0-30Days
05-Nov-14,12-AUG-14.08:09:35,12-Aug-14,85,61-90Days
05-Nov-14,16-DEC-13.08:09:26,16-Dec-13,324,181-365Days
05-Nov-14,18-DEC-13.03:09:23,18-Dec-13,322,181-365Days

我正在努力寻找＆＃34; No of Days＆＃34;但是被击中了

awk -F, -v q='"' '{
 c="date -d"q$3q" +%s";c|getline d1;close(c); 
 c="date -d"q05-NOV-14q" +%s";c|getline d2;close(c);
 printf "%s,%d\n", $0,(d2-d1)/3600/24}' Input.csv

期望的输出：

基于老化桶的产品和材料计数：

Product,Material,0-30Days,31-60Days,61-90Days,91-180Days,181-365Days,365-730Days,Greaterthan>730Days
ab,pq,0,2,0,1,0,0,1
cd,rs,1,0,1,0,2,0,0

我正在寻找你的建议，没有Perl / Python访问!!!

编辑＃1：感谢gboffi的输入，在执行下面的脚本时，我得到了＃34; elapsed_days＆＃34;所有订单项均为16410.3 ...请建议

awk -F, 'NR==1 {print}
         NR>1  {date=$3;
                gsub("[-.]"," ",date);
                printf $0 ",";system("date --date=\"" date "\" +%s")}
'  $filename | awk -F, -v OFS=, -v now=`date +%s` '
         NR==1 {print $0 ",elapsed_days"}
         NR>1  {$8=now-$8; $8=$8/24/3600;print $0}' Input.csv

输出 - 编辑＃1：

Des11,Des22,DateIn,Product,Material,Loc11,Loc22,elapsed_days
10,a,15-SEP-14.11:09:06,ab,pq,yyy,zzz,16410.3
20,a,23-SEP-14.08:09:35,ab,pq,yyy,zzz,16410.3
10,a,15-MAY-14.08:09:26,ab,pq,yyy,zzz,16410.3
62,a,17-FEB-12.03:09:23,ab,pq,yyy,zzz,16410.3
10,a,04-NOV-14.11:09:06,cd,rs,yyy,zzz,16410.3
20,a,12-AUG-14.08:09:35,cd,rs,yyy,zzz,16410.3
10,a,16-DEC-13.08:09:26,cd,rs,yyy,zzz,16410.3
62,a,18-DEC-13.03:09:23,cd,rs,yyy,zzz,16410.3

Answer 1

我有两个通过的解决方案

awk -F, 'NR==1 {print}
         NR>1  {date=$3;
                gsub("[-.]"," ",date);
                printf $0 ",";system("date --date=\"" date "\" +%s")}
'  $filename | awk -F, -v OFS=, -v now=`date +%s` '
         NR==1 {print $0 ",elapsed_days"}
         NR>1  {$8=now-$8; $8=$8/24/3600;print $0}'

当然，如果您有$8天数，则可以根据需要格式化最终输出。

回应OP问题

从我的终端复制并粘贴以下内容

我向您展示我的数据版本，从原始帖子中复制并粘贴，

% cat dates
Des11,Des22,DateIn,Product,Material,Loc11,Loc22
10,a,15-SEP-14.11:09:06,ab,pq,yyy,zzz
20,a,23-SEP-14.08:09:35,ab,pq,yyy,zzz
10,a,15-MAY-14.08:09:26,ab,pq,yyy,zzz
62,a,17-FEB-12.03:09:23,ab,pq,yyy,zzz
10,a,04-NOV-14.11:09:06,cd,rs,yyy,zzz
20,a,12-AUG-14.08:09:35,cd,rs,yyy,zzz
10,a,16-DEC-13.08:09:26,cd,rs,yyy,zzz
62,a,18-DEC-13.03:09:23,cd,rs,yyy,zzz

我只执行2阶段管道的第一部分

% awk -F, 'NR==1 {print}
           NR>1  {date=$3;
                  gsub("[-.]"," ",date);
                  printf $0 ",";system("date --date=\"" date "\" +%s")}
' dates 
Des11,Des22,DateIn,Product,Material,Loc11,Loc22
10,a,15-SEP-14.11:09:06,ab,pq,yyy,zzz,1410772146
20,a,23-SEP-14.08:09:35,ab,pq,yyy,zzz,1411452575
10,a,15-MAY-14.08:09:26,ab,pq,yyy,zzz,1400134166
62,a,17-FEB-12.03:09:23,ab,pq,yyy,zzz,1329444563
10,a,04-NOV-14.11:09:06,cd,rs,yyy,zzz,1415095746
20,a,12-AUG-14.08:09:35,cd,rs,yyy,zzz,1407823775
10,a,16-DEC-13.08:09:26,cd,rs,yyy,zzz,1387177766
62,a,18-DEC-13.03:09:23,cd,rs,yyy,zzz,1387332563

请注意在最后一个字段上方的输出中，其中包含系统date命令的输出

我最终执行整个管道，每行的经过天数不同你的手术出了什么问题？查看日期命令的输出，例如date --date="15 SEP 14 11:09:06" +%s，如果这不是问题，还有什么？

% awk -F, 'NR==1 {print}
           NR>1  {date=$3;
                  gsub("[-.]"," ",date);
                  printf $0 ",";system("date --date=\"" date "\" +%s")}
' dates | awk -F, -v OFS=, -v now=`date +%s` '
          NR==1 {print $0 ",elapsed_days"}
          NR>1  {$8=now-$8; $8=$8/24/3600;print $0}'
Des11,Des22,DateIn,Product,Material,Loc11,Loc22,elapsed_days
10,a,15-SEP-14.11:09:06,ab,pq,yyy,zzz,81.9347
20,a,23-SEP-14.08:09:35,ab,pq,yyy,zzz,74.0593
10,a,15-MAY-14.08:09:26,ab,pq,yyy,zzz,205.059
62,a,17-FEB-12.03:09:23,ab,pq,yyy,zzz,1023.23
10,a,04-NOV-14.11:09:06,cd,rs,yyy,zzz,31.893
20,a,12-AUG-14.08:09:35,cd,rs,yyy,zzz,116.059
10,a,16-DEC-13.08:09:26,cd,rs,yyy,zzz,355.018
62,a,18-DEC-13.03:09:23,cd,rs,yyy,zzz,353.226
%

根据天数计算老化桶

1 个答案: