Question

在我的应用程序中，我使用以下代码来检索当前日期和日期： -

NSDate *today1 = [NSDate date]; NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init]; [dateFormat setDateFormat:@"dd/MM/yyyy :EEEE"]; NSString *dateString11 = [dateFormat stringFromDate:today1];
NSLog(@"date: %@", dateString11);
//[dateFormat release];
NSCalendar *gregorian11 = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];  
NSDateComponents *components1 = [gregorian11 components:NSWeekdayCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today1];
[components1 setDay:([components1 day]-([components1 weekday]-1))];

NSDate *beginningOfWeek1 = [gregorian11 dateFromComponents:components1];
NSDateFormatter *dateFormat_first = [[NSDateFormatter alloc] init];
[dateFormat_first setDateFormat:@"dd/MM/yyyy :EEEE"];
NSString *dateString_first = [dateFormat_first stringFromDate:beginningOfWeek1];

NSLog(@"First_date: %@", dateString_first);
[components1 setDay:([components1 day]-([components1 weekday]-1) + 6)]; now =[gregorian dateFromComponents:components1]; [format setDateFormat:@"dd/MM/yyyy :EEEE"]; dateString = [format stringFromDate:now]; NSLog(@" week Last_date: %@", dateString);

但是使用上面的代码我只得到当天和日期和一周的第一天，但我需要得到一周的最后一天。但它给出了错误的输出。我的代码在哪里错了，需要进行哪些修改才能获得最后一天/哪一周？

Answer 1

当您致电setDay时：您有时会将其设置为负数日。我不知道setDay和/或dateFromComponents：是否会处理它。

要为过去（或将来）的日期/时间创建NSDate，您可以减去（或添加）您想要返回（或转发）的秒数，如下所示：

// convert to seconds
NSTimeInterval tmpSecs = [[NSDate date] timeIntervalSinceReferenceDate];
// Shift the date/time (in seconds) to a new date X days away:
tmpSecs += daysOffset * 86400;  // 86400 seconds per day
// convert back to NSDate and return the result
return [NSDate dateWithTimeIntervalSinceReferenceDate:tmpSecs];

如何找到iPhone中的最后一天？

1 个答案: