如何在sql中获得上周的最后一天?

时间:2011-05-07 23:54:37

标签: sql sql-server tsql

如何在sql中获取上周的最后一个日期?我的意思是使用查询的最后一个星期日日期?

10 个答案:

答案 0 :(得分:37)

无论实际的DATEFIRST设置如何,最后一个星期日都可以这样找到:

SELECT DATEADD(day,
               -1 - (DATEPART(weekday, GETDATE()) + @@DATEFIRST - 2) % 7,
               GETDATE()
              ) AS LastSunday

GETDATE()替换为参数@date,以获取特定日期之前的最后一个星期日。

答案 1 :(得分:20)

上周日哪个是“上周”的结尾

SELECT DATEADD(wk, DATEDIFF(wk, 6, CURRENT_TIMESTAMP), 6) AS LAST_SUNDAY

本周假设周一周刊格式

SELECT DATEADD(wk, DATEDIFF(wk, 7, CURRENT_TIMESTAMP), 7) AS START_OF_WEEK
SELECT DATEADD(wk, DATEDIFF(wk, 6, CURRENT_TIMESTAMP), 6 + 7) AS END_OF_WEEK

<强>结果

START_OF_WEEK
-----------------------
2011-05-02 00:00:00.000

END_OF_WEEK
-----------------------
2011-05-08 00:00:00.000

解释巫毒的示例使用此方法将上述SQL更改为所需的周开始和周末的星期几

  • 以下示例列出当前周(星期日至星期六)的星期几
  • 如果实际的END_OF_WEEK是下周日周六,那么你需要+7到本周的价值。 (参见上面的END_OF_WEEK示例。)

SQL

SELECT DATEADD(wk, DATEDIFF(wk, -2, CURRENT_TIMESTAMP), -2) AS DAY_OF_WEEK /* Saturday */
SELECT DATEADD(wk, DATEDIFF(wk, -1, CURRENT_TIMESTAMP), -1) AS DAY_OF_WEEK /* Sunday */
SELECT DATEADD(wk, DATEDIFF(wk, 0, CURRENT_TIMESTAMP), 0) AS DAY_OF_WEEK /* Monday */
SELECT DATEADD(wk, DATEDIFF(wk, 1, CURRENT_TIMESTAMP), 1) AS DAY_OF_WEEK /* Tuesday */
SELECT DATEADD(wk, DATEDIFF(wk, 2, CURRENT_TIMESTAMP), 2) AS DAY_OF_WEEK /* Wednesday */
SELECT DATEADD(wk, DATEDIFF(wk, 3, CURRENT_TIMESTAMP), 3) AS DAY_OF_WEEK /* Thursday */
SELECT DATEADD(wk, DATEDIFF(wk, 4, CURRENT_TIMESTAMP), 4) AS DAY_OF_WEEK /* Friday */
SELECT DATEADD(wk, DATEDIFF(wk, 5, CURRENT_TIMESTAMP), 5) AS DAY_OF_WEEK /* Saturday */
SELECT DATEADD(wk, DATEDIFF(wk, 6, CURRENT_TIMESTAMP), 6) AS DAY_OF_WEEK /* Sunday */
SELECT DATEADD(wk, DATEDIFF(wk, 7, CURRENT_TIMESTAMP), 7) AS DAY_OF_WEEK /* Monday */
SELECT DATEADD(wk, DATEDIFF(wk, 8, CURRENT_TIMESTAMP), 8) AS DAY_OF_WEEK /* Tuesday */
SELECT DATEADD(wk, DATEDIFF(wk, 9, CURRENT_TIMESTAMP), 9) AS DAY_OF_WEEK /* Wednesday */
SELECT DATEADD(wk, DATEDIFF(wk, 10, CURRENT_TIMESTAMP), 10) AS DAY_OF_WEEK /* Thursday */
SELECT DATEADD(wk, DATEDIFF(wk, 11, CURRENT_TIMESTAMP), 11) AS DAY_OF_WEEK /* Friday */
SELECT DATEADD(wk, DATEDIFF(wk, 12, CURRENT_TIMESTAMP), 12) AS DAY_OF_WEEK /* Saturday */
etc...

答案 2 :(得分:3)

以下是关于如何执行此操作的精彩文章:

http://www.objectreference.net/post/SQL-Find-last-week-date-range.aspx

您可能希望使用@StartOfPrevWeek变量。

答案 3 :(得分:2)

DECLARE @LastSunday DATETIME 

-- This will get the previous Sunday with time as 23:59:59 
SELECT @LastSunday = Dateadd(SECOND, -1, Dateadd(WK, Datediff(WK, 6, 
                                                     CURRENT_TIMESTAMP) 
                                                , 7)) 

SELECT @LastSunday 

-- This gets the monday prior to it and time of 00:00:00 
SELECT Dateadd(SECOND, 1, Dateadd(DAY, -7, @LastSunday)) 
-- This will make you time spans between eg, Monday 16/07/2012 00:00:00 through to Sunday 22/07/2012 23:59:59
-- Then use them in your WHERE clause like this 
-- SELECT X,Y,Z From SomeTable 
-- WHERE DateField BETWEEN @PreviousMondayToLastSunday AND @LastSunday 

答案 4 :(得分:1)

要获得上一个星期日,或者今天如果今天是星期天,请尝试这个

DATEADD(day,- (DATEPART(dw,getdate()) + @@DATEFIRST -1) % 7, getdate())

答案 5 :(得分:0)

使用合适的日历表,SQL更简单。没有伏都教。

select max(cal_date) end_of_last_week
from calendar
where (cal_date < current_date and day_of_week = 'Sun');

end_of_last_week
--
2011-05-01

答案 6 :(得分:0)

SELECT (DATEADD(DAY, ((DATEPART(dw, @Date) - 1) * -1), @Date))

答案 7 :(得分:0)

这将为您提供指定日期和时间的下一个珍贵星期五

DECLARE @PREVIOUS int, @dtmStart datetime,@dtmEnd datetime, @NEXT int;
SET @dtmStart = '12/10/2013';
SET @dtmEnd = '12/11/2013';

select @PREVIOUS = datepart(dw,@dtmStart)
 WHILE @PREVIOUS <> 6
BEGIN 
    SET @dtmStart = DATEADD(day , -1 ,@dtmStart)
    SET @PREVIOUS = datepart(dw,@dtmStart)
  CONTINUE 
END 
select @dtmStart

 SELECT @NEXT = DATEPART(dw, @dtmEnd)
   WHILE @NEXT <> 6
BEGIN 
    SET @dtmEnd = DATEADD(day , 1 ,@dtmEnd)
    SET @NEXT = datepart(dw,@dtmEnd)
  CONTINUE 
END 
select @dtmEnd

答案 8 :(得分:-1)

以下是获取上周六日期的代码。此方法与数据库的设置无关。

declare @lastSaturday date,
        @today date,
        @todayName varchar(20);

select  @todayName = datename(weekday, getdate()), @today = getdate();

select  
            case @todayName 
                when 'Saturday' then @today
                when 'Sunday' then dateadd(day,-1,@today)
                when 'Monday' then dateadd(day,-2,@today)
                when 'Tuesday' then dateadd(day,-3,@today)
                when 'Wednesday' then dateadd(day,-4,@today)
                when 'Thursday' then dateadd(day,-5,@today)
                when 'Friday' then dateadd(day,-6,@today)
            end  as LastSaturday;

答案 9 :(得分:-2)

SET @EndDate = GETDATE()-DatePart(dw, GETDATE());