Question

我有一个问题是在Windows手机中随机显示几个网格。我创建了自己的代码，它工作正常，但并不简单。也许有一种更简单的方法来在Windows手机中显示随机网格。

这就是我的应用所需：

我想点击一个按钮来显示随机网格。当我再次单击时，它应显示另一个网格并隐藏前一个网格。它现在应该显示任意网格两次。

这是我自己的代码：

List<int> number = new List<int> { 1,2,3,4,5 }; //create list
private void Button_Click_2(object sender, RoutedEventArgs e)
{
    int numberrandom;
    Random bsd = new Random();
    if (number.Count > 0) // get random number from (numberlist) without repetition
    {
        int fIndex = bsd.Next(0, number.Count); 

        numberrandom = number[fIndex]; 
        txtbox1.Text = numberrandom.ToString(); // show random number at txtbox
        number.RemoveAt(fIndex);            
    }
    else 
    {
        messagebox.show("no more grid show");
    }

    int a = Convert.ToInt32(txtbox1.Text); // convert number txtbox from string to int
    int val = a;
    switch (val)
    {
        case 1: //show grid 1
            grid1.Visibility = Visibility.Visible; 
            grid2.Visibility = Visibility.Collapsed;
            grid3.Visibility = Visibility.Collapsed;
            grid4.Visibility = Visibility.Collapsed;
            grid5.Visibility = Visibility.Collapsed;
        break;
        case 2: //show grid 2
            grid1.Visibility = Visibility.Collapsed;
            grid2.Visibility = Visibility.Visible;
            grid3.Visibility = Visibility.Collapsed;
            grid4.Visibility = Visibility.Collapsed;
            grid5.Visibility = Visibility.Collapsed;
            break;
        case 3: //show grid 3
            grid1.Visibility = Visibility.Collapsed;
            grid2.Visibility = Visibility.Collapsed;
            grid3.Visibility = Visibility.Visible;
            grid4.Visibility = Visibility.Collapsed;
            grid5.Visibility = Visibility.Collapsed;
        break;
        case 4: //show grid 4
            grid1.Visibility = Visibility.Collapsed;
            grid2.Visibility = Visibility.Collapsed;
            grid3.Visibility = Visibility.Collapsed;
            grid4.Visibility = Visibility.Visible;
            grid5.Visibility = Visibility.Collapsed;
        break;
        case 5: //show grid 5
            grid1.Visibility = Visibility.Collapsed;
            grid2.Visibility = Visibility.Collapsed;
            grid3.Visibility = Visibility.Collapsed;
            grid4.Visibility = Visibility.Collapsed;
            grid5.Visibility = Visibility.Visible;
        break;
    }

Answer 1

我认为您要做的只是在开始之前对整数列表进行随机排序。

List<int> lNumbers = New List<int> {1,2,3,4,5};
var rnd = New Random();
lNumbers = lNumbers.OrderBy(ob => rnd.Next()).ToList();

然后只保留一个索引计数器变量，并在每次单击该按钮时显示列表中的下一个。

虽然我对Winodws Phone不太熟悉，但我认为你可以使用FindControl来获得正确的gridview控件来隐藏，而右键则可以取消隐藏。

希望这有帮助。

:)大卫

PS - 我对Yate先生的回答唯一不喜欢的是：

foreach(var grid in grids) {
    grid.Visibility = Visibility.Collapsed;
}
grids[gridIndex].Visibility = Visibility.Visible;

您无需将所有网格可见性设置为Collpased。只有最后一个：

if (gridIndex > 0) {
    grids[gridIndex - 1].Visibility = Visibility.Collapsed;
}
grids[gridIndex].Visibility = Visibility.Visible;

Answer 2

您的代码确实可以简化。例如，您可以将所有网格放在一个列表中并在其上循环以设置可见性：

List<int> number = new List<int> { 0, 1, 2, 3, 4 }; //create list
private void Button_Click_2(object sender, RoutedEventArgs e)
{
    int numberrandom;
    Random bsd = new Random();

    if (number.Count > 0) // get random number from (numberlist) without repetition
    {
        int fIndex = bsd.Next(0, number.Count); 

        numberrandom = number[fIndex]; 
        txtbox1.Text = (numberrandom + 1).ToString(); // show random number at txtbox
        number.RemoveAt(fIndex);
    }
    else 
    { 
        MessageBox.Show("no more grid show");
    }

    var grids = new List<Grid> { grid1, grid2, grid3, grid4, grid5 };

    for (int i = 0; i < grids.Count; i++)
    {
        grids[i].Visibility = i == numberrandom ? Visibility.Visible : Visibility.Collapsed;
    }
}

Answer 3

您可以进行一些改进：

List<Grid> grids = new List<Grid> { grid1, grid2, grid3, gridN ... };
int gridIndex = 0;

void Load() {
    grids.Shuffle(); // use the extension method linked below
}

void Button_Click_2(object sender, RoutedEventArgs e) {
    if (gridIndex >= grids.Count)
        return;

    if (gridIndex > 0) {
        grids[gridIndex - 1].Visibility = Visibility.Collapsed;
    }
    grids[gridIndex].Visibility = Visibility.Visible;
    gridIndex++;
}

您需要显示原始网格号吗？如果没有，上面的代码要简单得多。这是Shuffle（）扩展方法，我是从this answer得到的：

public static void Shuffle<T>(this IList<T> list)  
{  
    Random rng = new Random();  
    int n = list.Count;  
    while (n > 1) {  
        n--;  
        int k = rng.Next(n + 1);  
        T value = list[k];  
        list[k] = list[n];  
        list[n] = value;  
    }  
}

显示随机网格c＃

3 个答案: