Question

我正在使用oracle SQL，我有以下查询：

select replace(replace('count(distinct <thiscol>) over (partition by <nextcol>) / count(*) over () as <thiscol>_<nextcol>,',
                       '<thiscol>', column_name
                      ), '<nextcol>', lead(column_name) over (order by column_id)
              )
from all_tab_columns atc
where table_name = 'mytable'

输出应该是如下的查询：

select id,
       count(distinct name2) over (partition by name3) / count(*) over (),
       count(distinct name3) over (partition by name4) / count(*) over (),
       . . .
from mytable;

我希望得到而不是：

count(distinct name2) over (partition by name3) / count(*) over ()

此查询：

count(distinct name3) over (partition by name2) / count(*) over ()

任何人都可以建议如何替换列值的顺序？（<thiscol>和<nextcol>）。我尝试将<thiscol>替换为<nextcol>，但它给了我相同的结果。我尝试了许多其他成功的事情。

任何？

Answer 1

那是真的奇怪。相反，让我们按相反的顺序排序：

select replace(replace('count(distinct <thiscol>) over (partition by <nextcol>) / count(*) over () as <thiscol>_<nextcol>,',
                       '<thiscol>', column_name
                      ), '<nextcol>', lead(column_name) over (order by column_id desc)
              )
from all_tab_columns atc
where table_name = 'mytable';

请注意排序中的desc。

替换Oracle SQL中的函数

1 个答案: