Question

我正在尝试连接2个表并创建一个返回产品最低值的新字段。我尝试了很多变化，似乎无法让它发挥作用。

SELECT DISTINCT VENDOR.*, PRODUCT.P_PRICE, PRODUCT.LOWEST_PRICE AS MIN(PRODUCT.P_PRICE)
FROM PRODUCT
INNER JOIN VENDOR
ON VENDOR.V_CODE = PRODUCT.V_CODE
ORDER BY VENDOR.V_NAME

Answer 1

如果您要按供应商寻找最低价格，请使用group by和min：

SELECT  VENDOR.V_NAME,  MIN(PRODUCT.P_PRICE) AS LOWEST_PRICE 
FROM PRODUCT
INNER JOIN VENDOR
ON VENDOR.V_CODE = PRODUCT.V_CODE
GROUP BY VENDOR.V_NAME
ORDER BY VENDOR.V_NAME

Answer 2

您可以使用此功能，这将从最低价格供应商产品订购

SELECT  VENDOR.V_NAME,  MIN(PRODUCT.P_PRICE) AS LOWEST_PRICE 
FROM VENDOR
INNER JOIN PRODUCT
ON VENDOR.V_CODE = PRODUCT.V_CODE
GROUP BY VENDOR.V_NAME
ORDER BY LOWEST_PRICE

SQL FIDDLE： - http://sqlfiddle.com/#!3/467c8/2

Answer 3

不知道您的架构是如何定义的，请尝试：

SELECT 
    VENDOR.V_NAME, 
    PRODUCT.P_PRICE AS [VENDOR PRICE], 
    MIN(PRODUCT.P_PRICE) AS [LOWEST PRICE]
FROM 
    PRODUCT 
    INNER JOIN VENDOR ON VENDOR.V_CODE = PRODUCT.V_CODE 
GROUP BY
    VENDOR.V_NAME,PRODUCT.P_PRICE
ORDER BY 
    VENDOR.V_NAME

Answer 4

如果您想要每个供应商的最低价格产品，我建议使用窗口功能：

select pv.*
from (select v.v_name, p.p_name, p.p_price
             row_number() over (partition by p.v_code order by p.p_price asc) as seqnum
      from vendor v join
           product p
           on v.v_code = p.v_code
     ) pv
where seqnum = 1

列出供应商，以及价格最低的产品SQL

4 个答案: