Question

请考虑一个包含两列的供应商表：VendorName和PayableAmount

我正在寻找一个查询，该查询返回按PayableAmount降序排列的前十名供应商和其他应付金额的总和为＆＃34;其他＆＃34;在第11行。

显然，sum of PayableAmount表中的Vendors应该等于sum of PayableAmount中的Query。

Answer 1

从技术上讲，可以在一个查询中执行此操作：

declare @t table (
    Name varchar(50) primary key,
    Amount money not null
);

-- Dummy data
insert into @t (Name, Amount)
select top (20) sq.*
from (
select name, max(number) as [Amount]
from master.dbo.spt_values
where number between 100 and 100000
    and name is not null
group by name
) sq
order by newid();

-- The table itself, for verification
select * from @t order by Amount desc;

-- Actual query
select top (11)
    case when sq.RN > 10 then '<All others>' else sq.Name end as [VendorName],
    case
        when sq.RN > 10 then sum(sq.Amount) over(partition by case when sq.rn > 10 then 1 else 0 end)
        else sq.Amount
    end as [Value]
from (
    select t.Name, t.Amount, row_number() over(order by t.Amount desc) as [RN]
    from @t t
    ) sq
order by sq.RN;

它甚至适用于从2005年开始的任何SQL Server版本。但是，在现实生活中，我更愿意分别计算这两个部分，然后UNION。

Answer 2

这将执行您正在寻找的查询。首先提取前10名中的那些，然后UNION将结果与排名较高的供应商进行比较，但调用'Other'

WITH rank AS (SELECT
VendorName,
PayableAmount,
ROW_NUMBER() OVER (ORDER BY PayableAmount DESC) AS rn
FROM vendors)

SELECT VendorName,
rn,
PayableAmount
FROM
rank WHERE rn <= 10

UNION

SELECT VendorName, 11 AS rn, PayableAmount 
FROM
  (
  SELECT 'Other' AS VendorName,
  SUM(PayableAmount) AS PayableAmount
  FROM
  rank WHERE rn > 10
  ) X11

ORDER BY rn

这已在SQLFiddle中测试过。

Answer 3

这是第11行

我没看过它

declare @i int
set @i=
(select sum(x.PayableAmount)
from
(select * from table
except
select top 10 *from table
order by PayableAmount desc) as x)

select 'another',@i

对十大供应商进行排序，并将供应商视为“其他”

3 个答案: