错误的语法错误“as”Postgres

Question

我在这里是postgres是我的查询

update cust_final_1 as cust set cust.enure_days=datediff(day,1date,current_date)
from  card as card join  cust_final_1 as cust on cust.cust_id=card.cardh_cust_id
left join bt_time as tim on card.cardh_act_dt=tim.time_id

执行它时会出现错误，因为＆＃34;＆＃34;＆＃34;

附近的语法不正确

错误是什么

Answer 1

这应该适合你：

UPDATE cust
SET cust.enure_days = datediff(day, 1 DATE, CURRENT_DATE)
FROM card AS card
INNER JOIN cust_final_1 AS cust
    ON cust.cust_id = card.cardh_cust_id
LEFT JOIN bt_time AS tim
    ON card.cardh_act_dt = tim.time_id

只需在UPDATE关键字

后面用别名替换表名

Answer 2

不确定你的专栏是什么意思，但是这里有。我假设“1date”是您希望与

区别开来的日期

UPDATE cust_final_1 
SET enure_days=current_date - "1date" -- datediff is not postgresql, just subtract if they are both dates
FROM card 
left join bt_time as tim on card.cardh_act_dt=tim.time_id
WHERE cust_final_1.cust_id=card.cardh_cust_id

我也对左连接表示怀疑。为什么这样？如果bt_time中没有相应的记录，并且该表中有“1date”，那么您将使用NULL更新记录。我建议使用INNER JOIN，这只是意味着丢失的记录不会做任何事情。