Question

我不小心点击ctrl z而不是ctrl c来停止python SimpleHTTPServer，它出现了

[1]  + 35296 suspended  python -m SimpleHTTPServer

现在我无法在端口8000正在使用的同一端口重启它

Traceback (most recent call last):
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/runpy.py",      line 162, in _run_module_as_main
"__main__", fname, loader, pkg_name)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/runpy.py", line 72, in _run_code
exec code in run_globals
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SimpleHTTPServer.py", line 220, in <module>
test()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SimpleHTTPServer.py", line 216, in test
BaseHTTPServer.test(HandlerClass, ServerClass)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 595, in test
httpd = ServerClass(server_address, HandlerClass)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 419, in __init__
self.server_bind()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 108, in server_bind
SocketServer.TCPServer.server_bind(self)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 430, in server_bind
self.socket.bind(self.server_address)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/socket.py", line 224, in meth
return getattr(self._sock,name)(*args)
socket.error: [Errno 48] Address already in use

如何停止此过程以便我可以再次使用端口8000？

由于

Answer 1

杀死这个过程。

kill 35296

或：

kill %1

Answer 2

此过程在后台暂停，您必须将其终止才能释放该端口。

如果您在同一个终端中，运行fg会将其置于最前面并重新激活它，让您通过 CTRL + C <正常中断它/ KBD>

如果你没有，你可以使用那个被打印的号码（进程ID或PID）来杀死它，但是你首先必须重新激活它，以便它可以做出反应： / p>

kill -CONT 35296
kill 35296

Answer 3

使用fg将它带到前台，然后你可以使用ctrl + c

将其杀死

python SimpleHTTPServer暂停，如何停止？

3 个答案: