Question

当我尝试运行代码时，它会不断重复，＆＃34;到目前为止，您已经猜到了＃34;当我只想重复一次。猜测时名称的输出应该是：secret_word = hello，然后在每个单词之后它应该是h ??? o或h？ll？

def get_secret_word():
    while True:
        secret_word = input('Please enter a word to be guessed\nthat does not contain ? or whitespace:')
    if not ('?' in secret_word or ' ' in secret_word or secret_word == ''):
        return secret_word


def is_game_over(wrong_guess, secret_word, output, chars_guessed):
    if wrong_guess == 7:
        print('You failed to guess the secret word:', secret_word)
        return True
    for guess in secret_word:
        if guess in chars_guessed:
            output += guess
        else:
            output += '?'
    if not ('?' in output):
        print('You correctly guessed the secret word:', secret_word)
        return True
    else:
        return False


def display_hangman(wrong_guess):
    if wrong_guess == 1:
        print('\n |')
     elif wrong_guess == 2:
        print('\n |', '\n O')
     elif wrong_guess == 3:
        print('\n |', '\n O', '\n |')
     elif wrong_guess == 4:
        print('\n |', '\n O', '\n/|')
     elif wrong_guess == 5:
        print('\n |', '\n O', '\n/|\\')
     elif wrong_guess == 6:
        print('\n |', '\n O', '\n/|\\', '\n/')
     elif wrong_guess == 7:
        print('\n |', '\n O', '\n/|\\', '\n/', '\\')

def display_guess(secret_word, chars_guessed):
    output = ''

    for guess in secret_word:
        if guess in chars_guessed:
            output += guess
        else:
            output += '\nSo far you have guessed: '
            for guess in chars_guessed:
                output += guess + ","
                print(output.strip(","))

def get_guess(secret_word, chars_guessed):
    while True:

        guess_character = input('Please enter your next guess: ')
        if guess_character == '':
            print('You must enter a guess.')
            continue
        elif len(guess_character) > 1:
            print('You can only guess a single character.')
        elif guess_character in chars_guessed:
            print('You already guessed the character:', guess_character)
        else:
            return guess_character

def main():
    wrong_guess = 0
    chars_guessed = []
    secret_word = get_secret_word()
    output = ''

    while not is_game_over(wrong_guess, secret_word, output, chars_guessed):
        display_hangman(wrong_guess)
        display_guess(secret_word, chars_guessed)
        guess_character = get_guess(secret_word, chars_guessed)
        chars_guessed.append(guess_character)
        chars_guessed.sort()
        if not guess_character in secret_word:
            wrong_guess += 1
            return wrong_guess
            pass


if __name__ == '__main__':
    main()

Answer 1

所以我能看到的问题是：

缩进问题（正如其他一些海报所指出的那样）：
- 带有if语句的get_secret_word（）函数
- display_hangman（）函数与所有elif的

还使用主函数

中的以下代码

 if not guess_character in secret_word:
            wrong_guess += 1
            return wrong_guess
            pass

这个退出了我的应用程序，据我所知，返回和传递行不需要。当做出错误猜测时， return 退出main函数，因此 pass 永远不会到达，因为 wrong_guess 是＆＃34;全球＆＃34; main函数中的变量新函数可用于函数中所有函数的活动时间长度。

对于重复循环，显示用户猜测它是你在display_guess()函数中循环的方式。在被猜测的字符不在秘密字中的情况下，它在所有内容上循环两次，一次用于外部for循环，然后再用于内部循环。

我认为您应该将 display_guess（）更改为如下所示。这样，用户将始终看到他们之前猜到的内容

def display_guess():
    output = "\nSo far you have guessed: "
    count = 0
    if len(chars_guessed) > 0:
        for guess in chars_guessed:

            if count < len(chars_guessed) and count != 0:
                output += ','
            output += guess
            count +=1
        print output

至于显示带有猜测字符的秘密字，其余部分显示为？＆＃39>，您似乎无法打印输出变量的值。 is_game_over（）功能随处可见。我还没有对它进行过测试，但在循环之后添加一个打印应该排除它。

在旁注上你可能希望在用户输入上添加验证，因为它除了数字和特殊字符

Hangman Python重复函数

1 个答案: