Question

对于作业，我需要写一个基本的HANGMAN游戏。这一切都有效，除了这一部分......

游戏应该为神秘词中的每个字母打印其中一个下划线（“_”）;然后当用户猜出（正确）字母时，它们将被放入。

E.G

假设这个词是“word”

用户猜测“W”

W _ _ _

用户猜测“D”

W _ _ D

然而，在许多情况下，一旦用户做了一些猜测，一些下划线就会丢失，所以最终会看起来像：

W _ D

而不是：

W _ _ D

我无法弄清楚我的代码的哪一部分正在实现这一点。任何帮助，将不胜感激！干杯！

这是我的代码：

import random

choice = None

list = ["HANGMAN", "ASSIGNEMENT", "PYTHON", "SCHOOL", "PROGRAMMING", "CODING", "CHALLENGE"]
while choice != "0":
    print('''
    ******************
    Welcome to Hangman
    ******************

    Please select a menu option:

    0 - Exit
    1 - Enter a new list of words
    2 - Play Game

    ''')
    choice= input("Enter you choice: ")

    if choice == "0":
        print("Exiting the program...")
    elif choice =="1":
        list = []
        x = 0
        while x != 5:
            word = str(input("Enter a new word to put in the list: "))
            list.append(word)
            word = word.upper()
            x += 1
    elif choice == "2":
        word = random.choice(list)
        word = word.upper()
        hidden_word = " _ " * len(word)
        lives = 6
        guessed = []

        while lives != 0 and hidden_word != word:
            print("\n******************************")
            print("The word is")
            print(hidden_word)
            print("\nThere are", len(word), "letters in this word")
            print("So far the letters you have guessed are: ")
            print(' '.join(guessed))
            print("\n You have", lives,"lives remaining")
            guess = input("\n Guess a letter: \n")
            guess = guess.upper()
            if len(guess) > 1:
                guess = input("\n You can only guess one letter at a time!\n Try again: ")
                guess = guess.upper()
            while guess in guessed:
                print("\n You have already guessed that letter!")
                guess = input("\n Please take another guess: ")
                guess = guess.upper()
            guessed.append(guess)
            if guess in word:
                print("*******************************")
                print("Well done!", guess.upper(),"is in the word")
                word_so_far = ""
                for i in range (len(word)):
                    if guess == str(word[i]):
                        word_so_far += guess
                    else:
                        word_so_far += hidden_word[i]
                hidden_word = word_so_far
            else:
                print("************************")
                print("Sorry, but", guess, "is not in the word")
                lives -= 1

        if lives == 0:
                print("GAME OVER! You ahve no lives left")
        else:
            print("\n CONGRATULATIONS! You have guessed the word")
            print("The word was", word)
            print("\nThank you for playing Hangman")
    else:
        choice = input("\n That is not a valid option! Please try again!\n Choice: ")

Answer 1

你有hidden_word = " _ " * len(word) 这意味着在两个字母的单词开头，你有[空格] [下划线] [空格] [空格] [下划线] [空格]。

当你执行word_so_far += hidden_word[i]时，对于i = 0，你会追加一个空格，而不是下划线。

最快的解决办法似乎是：

将hidden_word设置为_（＃{1}}）
打印出来时，请执行此操作 hidden_word = " _ " * len(word)添加下划线周围的空格

Answer 2

@Foon向您展示了解决方案的问题。

如果您可以将代码划分为小功能块，则可以更轻松地专注于那个任务，这样可以更轻松地进行测试。当您遇到特定任务的问题时，通过将问题变为函数来帮助隔离问题。

像这样。

word = '12345'
guesses = ['1', '5', '9', '0']

def hidden_word(word, guesses):
    hidden = ''
    for character in word:
        hidden += character if character in guesses else ' _ '
    return hidden

print(hidden_word(word, guesses))
guesses.append('3')
print(hidden_word(word, guesses))

Answer 3

下面的代码解决了这个问题，你可以根据你的需求做一些修改。如果单词中存在Guessed字母，那么这个字母将被添加到显示变量中。如果没有你可以给出警告。但请注意它可能会诱使您在 for 循环中编写 ELSE 语句（条件：如果猜测不在单词中）。如果您这样做，那么将重复 Else 语句中的对象，直到 For 循环停止。这就是为什么最好使用for 循环外的单独 IF 语句。

  word="banana"
  display=[]
  for i in word:
      display+="_"
  print(display)
  while True:
      Guess=input("Enter the letter:")
      for position in range(len(word)):
      if Guess==word[position]:
          display[position]=word[position]
      print(display)
      if Guess not in word:
         print("letter Doesn't exist")

HANGMAN赋值python

3 个答案: