Question

我正在编写一个汇编程序，可以生成所有可能的毕达哥拉斯三元组，我的问题是在运行一段时间后我得到了这个错误：
“Project.exe中0x00403484处的未处理异常：0xC0000005：访问冲突写入位置0x00190000。”

当我点击错误时，它会将我带到我的三重程序（mov A，eax）

我想知道是否有人可以帮我解决这个问题我不知道为什么可以在前7次写入它，但是第8次出现错误。

TITLE Program 3 Pythagorean Triples         (main.asm)

INCLUDE Irvine32.inc

.data

myMessage BYTE "Here is a list of all possible Pythagorean Triples: ",0dh,0ah,0 
myX     BYTE " x: ",0               
myY     BYTE " y: ",0
myZ     BYTE " z: ",0
myU     DWORD ?
myV     DWORD ?
mytempX DWORD ?
mytempY DWORD ?
mytempZ DWORD ?


.code

 main PROC 
 mov    edx, OFFSET myMessage
 call   WriteString
 mov    myU, 2
 dowh1: mov    eax, myU
    and    eax, 1
    jnz    else1
    mov    myV, 1
    jmp    dowh2
 else1: mov    myV, 2
 dowh2: call   gcd
    cmp    eax, 1
    jne    else2
    mov    eax, myU
    mov    ebx, myV
    call   triple
    jmp    enddo2
else2:  add    myV, 2
    mov    eax, myV
    cmp    eax, myU
    jb     dowh2
enddo2: add    myU, 1
    mov    eax, myU
    cmp    eax, 10
    jb     dowh1 

exit
main ENDP

GCD程序

gcd  PROC A:DWORD, B:DWORD

     mov  eax, myU
     mov  A, eax
     mov  ebx, myV
     mov  B, ebx

while1:  mov  ebx, B
     cmp  ebx, 0
     jna  endwh1
     mov  eax, A
     mov  edx, 0
     div  B
     xchg edx, B
     mov  A, edx
     jmp  while1
endwh1:  mov  eax, A
     ret

     exit
gcd  ENDP

三重程序

triple PROC U:DWORD, V:DWORD

    mov  eax, myU
    mov  U, eax
    mov  ebx, myV
    mov  V, ebx

    mov  eax, U
    mul  U
    mov  mytempX, eax
    mov  eax, V
    mul  V
    sub  mytempX, eax

    mov  eax, U
    mov  ecx, V
    mul  ecx
    add  eax, eax
    mov  mytempY, eax

    mov  eax, U
    mul  U
    mov  mytempZ, eax
    mov  eax, V
    mul  V
    add  mytempZ, eax

    mov  eax, mytempX
    cmp  eax, mytempY
    jna  ENDIF1
    mov  eax, mytempX
    xchg eax, mytempY
    mov  mytempX, eax

endif1: mov  edx, OFFSET myX
    call WriteString
    mov  eax, mytempX
    call WriteInt
    mov  edx, OFFSET myY
    call WriteString
    mov  eax, mytempY
    call WriteInt
    mov  edx, OFFSET myZ
    call WriteString
    mov  eax, mytempZ
    call WriteInt
    call CRLF
    ret

    exit
triple ENDP
END main

输出

 Here is a list of all possible Pythagorean Triples:
x: +3 y: +4 z: +5
x: +5 y: +12 z: +13
x: +8 y: +15 z: +17
x: +20 y: +21 z: +29
x: +12 y: +35 z: +37
x: +28 y: +45 z: +53
x: +16 y: +63 z: +65

PS。我希望我做的一切都是正确的，这是我第一次在这里发帖。

装配中的毕达哥拉斯三元组，访问冲突写入位置0x00190000

0 个答案: