Question

我正在使用以下代码将Ajax请求发送到PHP文件：

var d = "email=" + email + "&password=" + password;

        $.ajax({
            url: "login/c_login_form.php",
            data: d,
            type: "POST",
            success: function(str) {

                        if ( str === "#" ) { //# means success
                            alert("Login successful!");
                            return;
                        }
                        else {
                            //login failed
                            alert("Error logging in: " + str);
                            return;
                        }
                     },
            error: function(obj) {
                        alert("Failed to send Ajax request.");
                        return;
                     }
        });

PHP文件的内容是：

<?php
/*
*
* The controller file for login form
*
*/

if( isset( $_POST["email"] ) && isset( $_POST["password"] )) {

    $email = $_POST["email"];
    $password = $_POST["password"];

    //load the config file to read settings
    require_once($_SERVER['DOCUMENT_ROOT'] . '/hrms/lib/config.php');

    //connect to database
    $conn = mysqli_connect($db_host, $db_username, $db_password, $db_name);

    if(!$conn) {
        echo "Can't connect to database";
        return;
    }

    //check if employee is active
    $query = "SELECT employee.emp_id, role, is_active FROM employee INNER JOIN user ON employee.emp_id = user.emp_id WHERE email_bb = '{$email}' AND password = '{$password}'";

    if( $query === FALSE ) {
        echo "Failed to query database.";
        return;
    }

    $result = mysqli_query($conn, $query);

    if( $result === false ) {
        echo "No such user exists. Please re-check login details.";
        return;
    }

    $row = mysqli_fetch_assoc($result);

    if( (count($row) > 0 ) and ($row['is_active'] == "0") ) {
        echo "Employee not active anymore. Please contact HR.";
        return;
    }

    if( count($row) === 3 ) {
        //Everything looks okay. Process login now.
        $emp_id = $row['emp_id'];
        $role = $row['role'];

        //close connection
        mysqli_close($conn);

        session_start();
        $_SESSION['emp_id'] = $emp_id;
        echo "#";

        $path = $_SERVER['DOCUMENT_ROOT'] . '/hrms/dashboard.php?role={$role}';
        header("Location://{path}");
        die();      
    }
}
else {
    echo "Error. POST is not set.";
    return;
}

奇怪的是，如果我将PHP文件中的前两个语句设为echo "#"; return;，那么我就能看到“登录成功”消息。否则，即使我发送了正确的查询（在phpMyAdmin中验证），我仍然会收到错误“无法发送Ajax请求”。

知道可能导致它的原因吗？

Answer 1

发布回答以关闭此问题。问题确实与已发送的标头有关，因为我在同一个地方使用了echo和header功能。当我删除header部分并从JavaScript执行重定向时，它按预期工作。

无法向PHP文件发出Ajax请求

1 个答案: