I have the following HTML code:
<form action="mail/filesend.php" method="POST" accept-charset="utf-8" enctype="multipart/form-data" validate>
<div class="input-wrpr">
<input type="file" name="files[]">
</div>
<button type="submit">
Send File
</button>
</form>
And then the following file upload code in jQuery:
$(function () {
let files = null;
$('input[type="file"]').on('change' , (e) => {
files = e.target.files;
});
$('form').submit(function(e){
e.stopPropagation();
e.preventDefault();
let data = new FormData();
// files = $('input[type="file"]')[0].files;
$.each(files, function(key, value){
data.append(key, value);
});
console.log(data.getAll('0'));
// console.log(data);
$.ajax({
type: $(this).attr('method'),
url : $(this).attr('action'),
data: data,
cache: false,
dataType: 'json',
processData: false, // Don't process the files
contentType: false, // Set content type to false as jQuery will tell the server its a query string request
data : data
}).done(function(data){
// console.log(data);
if (! data.success) {
// console.log(data.errors);
/*for(let er in data.errors) {
console.log(data.errors[er])
}*/
console.log(data);
} else {
/* else condition fires if form submission is successful ! */
console.log(data.file);
}
}).fail(function(data){
console.log(data);
});
});
});
And the following PHP code for testing :
<?php
// You need to add server side validation and better error handling here
$data = array();
if(isset($_FILES['files'])) {
$data = array('file' => 'I a in if');
}
else {
$data = array('file' => 'I am in else');
}
echo json_encode($data);
?>
Now when i check my console i see that the PHP if condition is not passing , that is it is unable to detect:
isset($_POST['files'])
Why is this happening ? I have tried using isset($_FILES['files'])
, also I have tried renaming my html file input field to just files
instead of files[]
, but this does't seem to work , What am I doing wrong ?
I was following the tutorial HERE. But somehow the example I have created just does't work.
答案 0 :(得分:0)
Try to print_r($_FILES)
and check if it shows an array of file,
If it does, use the same key in $_FILES['same_key_here']
and it supposed to work,
Let me know if it doesn't
答案 1 :(得分:0)
If you want to send files, do something like this. This may help you.
var fileInput = $("#upload_img")[0]; // id of your file
var formData = new FormData();
formData.append("image_file",fileInput.files[0]); //'xmlfile' will be your key
Check in your php code like,
echo $_POST['image_file'];